Question

我有这样的json结果

{
   "modelList":["modelName1","modelName2"],
   "modelNamesList":["modelName1","modelName2"],
   "yearList":["2021","2020","2019","2018"]
}

我只需要上面对象的年份列表，所以我不知道该怎么做，谁能帮助我，谢谢

我做过这样的事情

home.component.ts

 export class HomeComponent implements OnInit {

    catlogData: any ={
                "modelList":["modelName1","modelName2"],
                "modelNamesList":["modelName1","modelName2"],
                "yearList":["2021","2020","2019","2018"]
    };


    ngOnInit(): void {}

home.component.html

<ul *ngFor="let a of catlogData">
    <li>year:{{a.yearList[i]}}
    </li>
</ul>

Answer 1

您可以直接从 class main(): def __init__(self): self.Width = int(input("Enter the Width:")) self.Height = int(input("Enter the Height:")) def area(self): a = (self.Width * self.Height) print("The area is", a) def perimeter(self): p = self.Width * 2 + self.Height * 2 print("The perimeter is", p) # instantiate a "main" object called "rectangle" rectangle = main() # call the "area" method rectangle.area() # call the "perimeter" method rectangle.perimeter() 访问 yearsList，因为它是一个 Object(catlogData)。如果您想迭代整个 catlogData.yearsList 对象，请检查此 answer

试试这个

catlogData

如何以角度迭代json对象内的数组值

1 个答案: