从字符串中检索以 $$, $ 开头的单词

Question

如何从查询中检索特殊字符串如下：

SELECT * from Employees  where yearNumber_MO = $$TestCheck_EmployeeMonth \n\t    and TESTING_STATUS = $$TestCheck_EmployeeMonth_Group \n\t    and WorkflowName = '$PMWorkName' \n\t    and CUSTOMFIELD = '$$TestCheck_EmployeeMonth_Region' \n\t    and Type = '$$TestCheck_EmployeeMonth_Type' \n\t  )

想要上面的返回stringarray with

TestCheck_EmployeeMonth, TestCheck_EmployeeMonth_Group, PMWorkName, TestCheck_EmployeeMonth_Region, TestCheck_EmployeeMonth_Type
 

Answer 1

您可以尝试使用正则表达式 (?<=[$]{1,2})[a-zA-Z_]+

Matcher matcher = Pattern.compile("(?<=[$]{1,2})[a-zA-Z_]+").matcher("SELECT * from Employees  where yearNumber_MO = $$TestCheck_EmployeeMonth \\n\\t    and TESTING_STATUS = $$TestCheck_EmployeeMonth_Group \\n\\t    and WorkflowName = '$PMWorkName' \\n\\t    and CUSTOMFIELD = '$$TestCheck_EmployeeMonth_Region' \\n\\t    and Type = '$$TestCheck_EmployeeMonth_Type' \\n\\t  )");
List<String> result = new ArrayList<>();
while(matcher.find()) {
    result.add(matcher.group());
}
return result;