如何在 python-telegram-bot 中接收来自用户的消息?

时间:2021-01-17 22:19:05

标签: python python-telegram-bot

我正在使用 python-telegram-bot

def delete(update: Update, context: CallbackContext) -> None:
    """delete account from database"""
    num = random.randrange(111111,999999)
    update.message.reply_text("Something to write here\n\n****" + str(num) + "****")
    time.sleep(10)
    if int(update.message.text) == num: #here update.message.text == '/cancel' and not the message user
        flag = delete_db(update.effective_user.id)
        if flag:
            update.message.reply_text('OK')
    else:
        update.message.reply_text('Something goes wrong or time is out')

如何强制更新消息?我认为有问题吗...

1 个答案:

答案 0 :(得分:0)

我根据电报社区的建议解决了这个问题,使用具有两个功能的会话处理程序,一个用于启动操作,第二个用于确认。

在定义主要中:

dispatcher.add_handler(
        ConversationHandler(
            entry_points = [MessageHandler(Filters.regex('^Cancel$'), delete)],
            states = {
                DELETE: [MessageHandler(Filters.text, random_number)],
            },
            fallbacks = [None], # here you can enter an /end function to break the process
            conversation_timeout = 30,
        ),
    )

启动函数'删除':

def delete(update: Update, context: CallbackContext):
    update.message.reply_text('some message')
    CallbackContext.chat_data = random.randrange(111111,999999)
    update.message.reply_text("some other message\n*" + str(CallbackContext.chat_data) + "*")
    return DELETE

保持字符串消息并与生成的随机数进行比较的函数:

def random_number(update: Update, context: CallbackContext):
    try:
        user_action = int(update.message.text)
        if user_action == CallbackContext.chat_data:
            #flag = delete_db(update.effective_user.id) # function to delete from database
            if flag:
                update.message.reply_text('Okay done')
        else:
            update.message.reply_text('Wrong number')
    except:
        update.message.reply_text('failed')    
    return ConversationHandler.END