Question

这是我的作业问题：

编写一个程序，模拟多次滚动一组六面骰子。程序应使用字典记录结果，然后显示结果。

输入：程序应提示掷骰子的数量和掷骰子的次数。

输出：

程序将显示每个可能值的滚动次数。输出格式必须如下所示：

第一列是骰子滚动时显示的数字。括号只能根据需要加宽，括号内的数字是右对齐的。请注意下面的示例中的最小值和最大值。

第二列是该值被滚动的次数。这一栏是正确的。

最后一列是该数字滚动的次数百分比。百分比显示精确到小数点后一位。

这是我到目前为止的代码：

import random
from math import floor, ceil
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
rand = float(0)
rolltotal = int(input("How many times do you want to roll? "))    
q = 0    
while q < rolltotal:
    q = q + 1
    rand = ceil(6*(random.random()))
    if rand == 1:    
        one = one + 1
    elif rand == 2:
        two = two + 1
    elif rand == 3:
        three = three + 1
    elif rand == 4:
        four = four + 1
    elif rand == 5:
        five = five + 1
    else:
        six = six + 1

total = one + two + three + four + five + six

print("[1]", one, " ",round(100*one/total, 1),"%")    
print("[2]", two, " ",round(100*two/total, 1),"%")
print("[3]", three, " ",round(100*three/total, 1),"%")
print("[4]", four, " ",round(100*four/total, 1),"%")
print("[5]", five, " ",round(100*five/total, 1),"%")    
print("[6]", six, " ",round(100*six/total, 1),"%")

我的问题是：我只知道如何掷骰子。我怎么能得到不止一个。

Answer 1

from collections import defaultdict
import random

dice = int(input("How many dice do you want to roll? "))
rolls = int(input("How many times do you want to roll them? "))

irange = xrange
sides = [1,2,3,4,5,6]

d = defaultdict(int)
for r in irange(rolls):
    d[sum( random.choice(sides) for d in irange(dice) )] += 1

total = float(rolls)
for k in sorted(d.keys()):
    print "[%d] %d %.1f%%" % (k, d[k], 100.0*d[k]/total)

Answer 2

您宁愿执行以下操作： -

loop=True
import random  #This allows python to import built in "random" function.
while loop is True:    
    dice=input("Which sided dice would you like to roll? (You can only choose 4,6 or 12) \n") # "\n" allows python to add a new line.
    if dice=="4":
         print("You have chosen to roll dice 4\nYour score is... \n", random.randint(1,4)) #This allows python to generate a random number from 1 to 4.
    elif dice=="6":
         print("You have chosen to roll dice 6\nYour score is...\n", random.randint(1,6)) #This allows python to generate a random number from 1 to 6.
    elif dice=="12":
        print("You have chosen to roll dice 12\nYour score is...\n", random.randint(1,12)) #This allows python to generate a random number from 1 to 12.
    else: print("Invalid option! Please try again!") 
    loop2=input("Do you want to roll again? (Yes or No) \n")
    if loop2=="yes" or loop2=="Yes": # "or" funtion allows python to accept any of the two answers input by the user.
       loop=True
    else: break    # This function allows program to close.

Python - 骰子模拟器

2 个答案: