[已编辑] 为简单起见，我将在此处包含整个文件：
choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
if not wrongEntryPlayer1 and not wrongEntryPlayer2:
print('\n')
print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
print('----------')
print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
print('----------')
print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
# above code is to print board layouts
if Is_Current_One:
print("Player 1's turn.\nChoose a number to put an X there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
print("Player 2's turn.\nChoose a number to put an O there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
if Is_Current_One:
if choices[choice - 1] == int:
try:
choices[choice - 1] = 'X'
wrongEntryPlayer1 = False
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
else:
print("Please choose a number that is empty.")
wrongEntryPlayer1 = True
else:
if choices[choice - 1] == int:
try:
choices[choice - 1] = 'O'
wrongEntryPlayer2 = False
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
else:
print("Please choose a number that is empty.")
wrongEntryPlayer2 = True
# code to toggle between True and False
Is_Current_One = not Is_Current_One
for pos_x in range(0, 3):
pos_y = pos_x * 3
# for row condition:
if (choices[pos_y] == choices[(pos_y + 1)]) and (
choices[pos_y] == choices[(pos_y + 2)]):
won = True
# column condition:
if (choices[pos_x] == choices[(pos_x + 3)]) and (
choices[pos_x] == choices[(pos_x + 6)]):
won = True
if ((choices[0] == choices[4] and choices[0] == choices[8])
or (choices[2] == choices[4] and choices[4] == choices[6])):
won = True
print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")
如果你真的阅读了代码，你会发现我正在制作一个井字游戏。
我已经声明了两个布尔变量：wrongEntryPlayer1 和 wrongEntryPlayer2，它们最初默认设置为 False，因为游戏刚刚开始。
玩这个游戏时，玩家需要输入一个整数，在游戏板上显示，在那里放一个X或O。
如果玩家不输入一个整数，程序就会崩溃，我不希望那样。相反，当他们没有输入整数时，我使用了 try 语句并打印了一条用户友好的消息。
发生这种情况时，我不希望 Python 重新打印游戏板，因此当玩家输入错误值时，我将相应的 wrongEntryPlayer 变量设置为 True。这样，如果任何一个玩家输入了错误的值，我将完全跳过打印游戏板。
但是，当我尝试运行它并在第一回合输入错误的值时，然后输入正确的值，游戏板仍然不显示。即使轮到玩家 2，游戏板仍然没有打印出来。
当玩家输入正确的值（整数）时，游戏板仍然不显示。
另外，当玩家输入已经被其他玩家占用的值时，程序应该提示玩家再次输入。相反，它只是跳过玩家的回合。
我是一个python初学者，所以有些代码可能看起来很傻。谁能帮助我并向我解释如何解决这个问题？谢谢！ 感谢 Sanetro，我原来的问题得到了解决。现在发生了另一个错误。详细问题发布在 Sanetro 回答的评论部分。我来这里是为了包含我的详细编辑代码。
choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
if not wrongEntryPlayer1 and not wrongEntryPlayer2:
print('\n')
print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
print('----------')
print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
print('----------')
print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
# above code is to print board layouts
if Is_Current_One:
print("Player 1's turn.\nChoose a number to put an X there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
print("Player 2's turn.\nChoose a number to put an O there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
if Is_Current_One:
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'X'
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer1 = True
else:
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'O'
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer2 = True
# code to toggle between True and False
if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
Is_Current_One = not Is_Current_One
for pos_x in range(0, 3):
pos_y = pos_x * 3
# for row condition:
if (choices[pos_y] == choices[(pos_y + 1)]) and (
choices[pos_y] == choices[(pos_y + 2)]):
won = True
# column condition:
if (choices[pos_x] == choices[(pos_x + 3)]) and (
choices[pos_x] == choices[(pos_x + 6)]):
won = True
if ((choices[0] == choices[4] and choices[0] == choices[8])
or (choices[2] == choices[4] and choices[4] == choices[6])):
won = True
print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")
[编辑 2] 好的，Sanetro，这实际上不是最终编辑。 我正在制作退出命令。当玩家输入 > 退出时，程序退出。我原本认为这会非常简单。你做一个while循环，当玩家输入退出时中断循环，然后就是这样！嗯，它不简单（至少对我而言）。由于choice = input(.....) in 循环，我不能将它放在循环之外（或在声明choice 变量之前），这很糟糕。我在顶部创建了一个新变量：exitTrigger 并将新行放入 while 循环中。它现在不起作用。当玩家输入退出时，它只是说请只输入有效的字段。可能是因为except语句仍然有效，我想添加一个条件来触发except语句，而我只想要exitTrigger为True时的except语句。我可以这样做吗？谢谢。
choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '11', '12', '13', '14', '15', '16']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
exitTrigger = False
while not won and not exitTrigger:
if not wrongEntryPlayer1 and not wrongEntryPlayer2:
print("Type exit to quit game")
print('\n')
print('|' + choices[0] + ' |' + choices[1] + ' |' + choices[2] + ' |' + choices[3] + ' |')
print('-------------')
print('|' + choices[4] + ' |' + choices[5] + ' |' + choices[6] + ' |' + choices[7] + ' |')
print('-------------')
print('|' + choices[8] + ' |' + choices[9] + '|' + choices[10] + '|' + choices[11] + '|')
print('-------------')
print('|' + choices[12] + '|' + choices[13] + '|' + choices[14] + '|' + choices[15] + '|')
# above code is to print board layouts
if Is_Current_One:
print("Player 1's turn.\nChoose a number to put an X there.")
try:
choice = int(input("> ").strip())
if choice == "exit":
exitTrigger = True
else:
wrongEntryPlayer1 = False
except ValueError:
if not exitTrigger:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer1 = True
continue
except IndexError:
if not exitTrigger:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer1 = True
continue
else:
print("Player 2's turn.\nChoose a number to put an O there.")
try:
choice = int(input("> ").strip())
if choice == "exit":
exitTrigger = True
else:
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer2 = True
continue
except IndexError:
if not exitTrigger:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer2 = True
continue
if not exitTrigger:
if Is_Current_One:
try: # <============ HERE
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'X'
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer1 = True
continue
except IndexError:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer1 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer1 = True
except: # <============ HERE
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer1 = True
continue
else:
try: # <============ HERE
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'O'
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer2 = True
continue
except IndexError:
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer2 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer2 = True
except: # <============ HERE
print("Please enter only valid fields from board (1-16)")
wrongEntryPlayer2 = True
continue
# code to toggle between True and False
if not exitTrigger:
if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
Is_Current_One = not Is_Current_One
for pos_x in range(0, 4):
pos_y = pos_x * 4
# for row condition:
if (choices[pos_y] == choices[(pos_y + 1)]) and (
choices[pos_y] == choices[(pos_y + 2)]) and (
choices[pos_y] == choices[(pos_y + 3)]):
won = True
# column condition:
if (choices[pos_x] == choices[(pos_x + 4)]) and (
choices[pos_x] == choices[(pos_x + 8)]) and (
choices[pos_x] == choices[(pos_x + 12)]):
won = True
if ((choices[0] == choices[5] and choices[0] == choices[10] and choices[0] == choices[15])
or (choices[3] == choices[6] and choices[3] == choices[9] and choices[3] == choices[12])):
won = True
if won:
print('\n')
print('|' + choices[0] + ' |' + choices[1] + ' |' + choices[2] + ' |' + choices[3] + ' |')
print('-------------')
print('|' + choices[4] + ' |' + choices[5] + ' |' + choices[6] + ' |' + choices[7] + ' |')
print('-------------')
print('|' + choices[8] + ' |' + choices[9] + '|' + choices[10] + '|' + choices[11] + '|')
print('-------------')
print('|' + choices[12] + '|' + choices[13] + '|' + choices[14] + '|' + choices[15] + '|')
# above code is to print board layouts
print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")
if exitTrigger:
print("Game quited")
顺便说一下，游戏板现在是 4*4 :D
答案 0 :(得分：2)
您的代码实际上有两个问题——首先，您寻求帮助的问题是由切换标志 Is_Current_One 引起的，即使玩家输入“错误”输入也是如此。换句话说，当玩家一输入“asdf”时，我们希望他们有机会再次输入“好”的输入，而不是立即切换到玩家二。在读取 if 的行上放置一个 if not wrongEntryPlayer1 and not wrongEntryPlayer2: 块。
第二个更大的问题是您对玩家输入是否为 int 的类型检查不起作用。首先，choices[choice - 1] == int 将数组中的值与类型进行比较，该类型始终为 False。其次，即使函数 isinstance(choices[choice-1], int) 也不起作用，因为 options 的每个成员都是字符串类型。因此，您应该使用字符串方法 choices[choice-1].isnumeric()，它将确定数组中的字符串是否为数字。 （或者，您可以测试它不是 x 或 o，但这更像是 Python 风格。）
我测试了这些更改，它们似乎有效。 pastebin
答案 1 :(得分：1)
[编辑] 我做了一些修复，它工作正常。
choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
if not wrongEntryPlayer1 and not wrongEntryPlayer2:
print('\n')
print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
print('----------')
print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
print('----------')
print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
# above code is to print board layouts
if Is_Current_One:
print("Player 1's turn.\nChoose a number to put an X there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
print("Player 2's turn.\nChoose a number to put an O there.")
try:
choice = int(input("> ").strip())
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
if Is_Current_One:
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'X'
wrongEntryPlayer1 = False
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
else:
print("Please choose a number that is empty.")
wrongEntryPlayer1 = True
else:
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'O'
wrongEntryPlayer2 = False
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
else:
print("Please choose a number that is empty.")
wrongEntryPlayer2 = True
# code to toggle between True and False
if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
Is_Current_One = not Is_Current_One
for pos_x in range(0, 3):
pos_y = pos_x * 3
# for row condition:
if (choices[pos_y] == choices[(pos_y + 1)]) and (
choices[pos_y] == choices[(pos_y + 2)]):
won = True
# column condition:
if (choices[pos_x] == choices[(pos_x + 3)]) and (
choices[pos_x] == choices[(pos_x + 6)]):
won = True
if ((choices[0] == choices[4] and choices[0] == choices[8])
or (choices[2] == choices[4] and choices[4] == choices[6])):
won = True
print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")
所以，我想为一些错误道歉。
我在互联网上找到了解决方案。在行 35 if choices[choice - 1] == int: 您必须像这样更改 if choices[choice - 1].isnumeric():，大多数变量都被视为对象。如果您想尝试使用 type()，您将收到错误消息。
接下来我删除了我的 choices_closed 这些东西 '='。这是完全没有必要的。你的想法比我做的更好。我说的是条件 if it's different then intiger it's fill'。我没有看到这些代码行：
# code to toggle between True and False
Is_Current_One = not Is_Current_One
我立即写道：
# code to toggle between True and False
if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
Is_Current_One = not Is_Current_One
我以为你和我一样困了，你没有注意到这一点。 我必须说这是我的错误
[编辑] 我在这里添加了一些例外：
if Is_Current_One:
try: # <============ HERE
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'X'
wrongEntryPlayer1 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer1 = True
except: # <============ HERE
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer1 = True
continue
else:
try: # <============ HERE
if choices[choice - 1].isnumeric():
try:
choices[choice - 1] = 'O'
wrongEntryPlayer2 = False
except ValueError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
except IndexError:
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
else:
print("Please choose a number that is empty.")
wrongEntryPlayer2 = True
except: # <============ HERE
print("Please enter only valid fields from board (0-8)")
wrongEntryPlayer2 = True
continue
也许这是最终编辑：P 当你发现更多东西时，我会尽力提供帮助。
答案 2 :(得分：0)
我认为而不是使用
if not wrongEntryPlayer1 and not wrongEntryPlayer2:
你应该使用：
if wrongEntryPlayer1 or wrongEntryPlayer2:
这将修复印刷电路板的部分。