您好我尝试了以下代码,并在列表视图中正确地将表中的记录列表作为输出。
但是当我评论Main_Activity类中的以下两个方法时,数据库记录不会被加载。 CREATETABLE(); insertData();
当我们在关闭它之后打开相同的应用程序时,我想知道是否必须再次创建表并插入相同的记录集。
有没有人知道为什么会这样发生......谢谢..
public class Main_Activity extends ListActivity {
private static String SAMPLE_TABLE_NAME = "PERSONS_TABLE";
private SQLiteDatabase sampleDB = null;
private List<String> results = new ArrayList<String>();
private Cursor cursor = null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
try
{
sampleDB = openOrCreateDatabase("NAME", MODE_PRIVATE, null);
createTable();
insertData();
lookupData();
this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,results));
}
catch (SQLiteException se)
{
Log.e(getClass().getSimpleName(), "Could not create or Open the database");
}
finally
{
if (sampleDB != null)
sampleDB.execSQL("DELETE FROM " + SAMPLE_TABLE_NAME);
sampleDB.close();
}
}
private void createTable()
{
sampleDB.execSQL("CREATE TABLE IF NOT EXISTS " +
SAMPLE_TABLE_NAME +
" (PERSON_NAME VARCHAR, " +
" COUNTRY VARCHAR, " +
" AGE INT(3));");
}
private void insertData()
{
sampleDB.execSQL("INSERT INTO " + SAMPLE_TABLE_NAME + " Values ('James','ENGLAND',25);");
sampleDB.execSQL("INSERT INTO " + SAMPLE_TABLE_NAME + " Values ('Dave','USA',18);");
sampleDB.execSQL("INSERT INTO " + SAMPLE_TABLE_NAME + " Values ('Jean-Paul','FRANCE',33);");
sampleDB.execSQL("INSERT INTO " + SAMPLE_TABLE_NAME + " Values ('Sergio','SPAIN',42);");
sampleDB.execSQL("INSERT INTO " + SAMPLE_TABLE_NAME + " Values ('Hitori','JAPAN',73);");
}
private void lookupData()
{
cursor = sampleDB.rawQuery("SELECT PERSON_NAME, COUNTRY, AGE FROM " +
SAMPLE_TABLE_NAME +
" where AGE > 10 ", null);
if (cursor != null)
{
if (cursor.moveToFirst())
{
do
{
String personName = cursor.getString(cursor.getColumnIndex("PERSON_NAME"));
String country = cursor.getString(cursor.getColumnIndex("COUNTRY"));
int age = cursor.getInt(cursor.getColumnIndex("AGE"));
results.add("" + personName + ", " + country + ", " + age);
}
while (cursor.moveToNext());
}
cursor.close();
}
}
}
答案 0 :(得分:1)
在你的try语句中,你正在创建数据库,填充它......然后在finally语句中删除所有记录。这就是你的数据库总是空着的原因。你应该记住,在try或catch之后最终会执行任何操作。