将List <t>序列化为XML,并将XML反转为List <t> </t> </t>

时间:2011-07-04 14:32:30

标签: c# list serialization deserialization

有谁知道我(或者是否可能)反转我在下面创建的XML

[Serializable()]
public class CustomDictionary
{
    public string Key { get; set; }
    public string Value { get; set; }
}

public class OtherClass
{
    protected void BtnSaveClick(object sender, EventArgs e)
    {
        var analysisList = new List<CustomDictionary>();

        // Here i fill the analysisList with some data
        // ...

        // This renders the xml posted below
        string myXML = Serialize(analysisList).ToString();
        xmlLiteral.Text = myXML;
    }

    public static StringWriter Serialize(object o)
    {
        var xs = new XmlSerializer(o.GetType());
        var xml = new StringWriter();
        xs.Serialize(xml, o);

        return xml;
    }
}

呈现的xml

<?xml version="1.0" encoding="utf-16"?>
<ArrayOfCustomDictionary xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <CustomDictionary>
    <Key>Gender</Key>
    <Value>0</Value>
  </CustomDictionary>
  <CustomDictionary>
    <Key>Height</Key>
    <Value>4</Value>
  </CustomDictionary>
  <CustomDictionary>
    <Key>Age</Key>
    <Value>2</Value>
  </CustomDictionary>
</ArrayOfCustomDictionary>

现在,经过几个小时的谷歌搜索并尝试我被卡住了(很可能我的大脑已经休假)。谁能帮助我如何将这个xml反转回List?

由于

2 个答案:

答案 0 :(得分:14)

只需反序列化:

public static T Deserialize<T>(string xml) {
  var xs = new XmlSerializer(typeof(T));
  return (T)xs.Deserialize(new StringReader(xml));
}

像这样使用:

var deserializedDictionaries = Deserialize<List<CustomDictionary>>(myXML);

答案 1 :(得分:0)