Question

我们有一个用pl / sql（oracle）编写的函数，如下所示：

CREATE OR REPLACE PROCEDURE folder_cycle_check (folder_key IN NUMBER, new_parent_folder_key IN NUMBER) IS
    parent_of_parent NUMBER;
    ILLEGAL_CYCLE EXCEPTION;
    CURSOR parent_c IS
    SELECT parent_folder_key FROM folder
        WHERE folder_key = new_parent_folder_key;
BEGIN

IF folder_key = new_parent_folder_key THEN
    RAISE ILLEGAL_CYCLE;
END IF;

FOR parent_rec IN parent_c LOOP
    BEGIN folder_cycle_check(folder_key, parent_rec.parent_folder_key); END;
END LOOP;

END;

现在，我必须在pl / pgsql（PostgreSQL）中重写相同的过程以实现类似的功能。请帮助我并发送pl / pgsql函数。

编辑（来自评论的格式化代码）

CREATE OR REPLACE FUNCTION folder_cycle_check(IN folder_key INTEGER, IN new_parent_folder_key INTEGER) 
  RETURNS VOID 
AS $procedure$ 
   DECLARE parent_of_parent INTEGER; 
   PARENT_C CURSOR FOR 
        SELECT parent_folder_key 
        FROM folder 
        WHERE folder_key = new_parent_folder_key; 
BEGIN 
    IF folder_key = new_parent_folder_key THEN 
        RAISE EXCEPTION 'ILLEGAL_CYCLE'; 
    END IF

    FOR parent_rec IN (SELECT parent_folder_key FROM folder WHERE folder_key = new_parent_folder_key) LOOP 
        PERFORM folder_cycle_check(folder_key,parent_rec.parent_folder_key); 
    END LOOP; 

    RETURN; 
END; 
$procedure$ 
LANGUAGE plpgsql;

Answer 1

这应该有效：

CREATE OR REPLACE FUNCTION folder_cycle_check (p_folder_key INT4, p_new_parent_folder_key INT4) RETURNS VOID AS $$
DECLARE
    v_parent_rec RECORD;
BEGIN
    IF folder_key = new_parent_folder_key THEN
        RAISE EXCEPTION 'ILLEGAL_CYCLE';
    END IF;
    FOR v_parent_rec IN SELECT parent_folder_key FROM folder WHERE folder_key = p_new_parent_folder_key LOOP
        PERFORM folder_cycle_check(folder_key, v_parent_rec.parent_folder_key)
    END LOOP;
    RETURN;
END;
$$ LANGUAGE plpgsql;

postgresql中的游标for循环

1 个答案: