Question

我有一个字符串变量，一些响应的开头有一个额外的字符。在所有情况下，所讨论的字符都是常量字符。变量是ICD代码。例如，我有 DG23 而不是 G23。

Stata 有没有办法去掉多余的 D 字符？

我的数据是这样的

<头>

ID	diag
1	DZ456
2	DG32
3	DY258
4	DD35
5	DS321
6	DD21
7	DA123

Answer 1

有关此领域的基本信息，请参阅 help string functions。

* Example generated by -dataex-. To install: ssc install dataex
clear
input byte d str5 diag
1 "DZ456"
2 "DG32" 
3 "DY258"
4 "DD35" 
5 "DS321"
6 "DD21" 
7 "DA123"
end

replace diag = substr(diag, 2, .) if substr(diag, 1, 1) == "D"

list 

     +----------+
     | d   diag |
     |----------|
  1. | 1   Z456 |
  2. | 2    G32 |
  3. | 3   Y258 |
  4. | 4    D35 |
  5. | 5   S321 |
     |----------|
  6. | 6    D21 |
  7. | 7   A123 |
     +----------+

Answer 2

字符串函数的替代方法是使用正则表达式，参见# Library library(networkD3) library(dplyr) # Make a connection data frame links <- data.frame( source=c("group_A","group_A", "group_B", "group_C", "group_C", "group_E"), target=c("group_C","group_D", "group_E", "group_F", "group_G", "group_H"), value=c(2,3, 2, 3, 1, 3) ) # From these flows we need to create a node data frame: it lists every entities involved in the flow nodes <- data.frame( name=c(as.character(links$source), as.character(links$target)) %>% unique() ) # With networkD3, connection must be provided using id, not using real name like in the links dataframe.. So we need to reformat it. links$IDsource <- match(links$source, nodes$name)-1 links$IDtarget <- match(links$target, nodes$name)-1 # Add a 'group' column to each connection: links$group <- as.factor(c("type_a","type_a","type_a","type_b","type_b","type_b")) # Add a 'group' column to each node. Here I decide to put all of them in the same group to make them grey nodes$group <- as.factor(c("my_unique_group")) # Give a color for each group: my_color <- 'd3.scaleOrdinal() .domain(["type_a", "type_b", "my_unique_group"]) .range(["#69b3a2", "steelblue", "grey"])' # Make the Network p <- sankeyNetwork(Links = links, Nodes = nodes, Source = "IDsource", Target = "IDtarget", Value = "value", NodeID = "name", colourScale=my_color, LinkGroup="group", NodeGroup="group") p。

help regex

从字符串响应中删除特定字符

2 个答案: