此代码输出是我在单击按钮时将显示的文本框中输入的内容。但是当我选择复选框时,我想要,然后在文本框中输入要渲染的值。
//View page: In this page JQuery for request&Responce type and i am displaying two text box and 1 check box and 1 button
<script type="text/javascript">
$(function(){
$('#selectAll').change(function () {
alert("value changed");//When i run this script only witht this alert function i am getting output but with this code i am unable to get the output what i expect
var options = {
target: '#result-user', // id of the div where we are going to display result
beforeSubmit: showRequest,
success: showResponse,
type: 'post',
resetForm: true
};
$('#form-user').ajaxForm(options); // id of the form we wish to submit
});
});
function showRequest(formData, jqForm, options) {
$("#result-user").empty().html('Loading....');
$("#form-user :input").attr("disabled", true); // disable all form inputs while loading
}
function showResponse(responseText, statusText, xhr, $form) {
$("#result-user").empty().html(responseText);
$("#form-user :input").attr("disabled", false);
}
</script>
</head>
<body>
<% using (Html.BeginForm("Index","Home",FormMethod.Post, new { id="form-user", name="form-user"})) {%>
<fieldset>
<legend>Fields</legend>
<div class="editor-label">
<%= Html.LabelFor(model => model.FirstName) %>
</div>
<div class="editor-field">
<%= Html.TextBoxFor(model => model.FirstName) %>
<%= Html.ValidationMessageFor(model => model.FirstName) %>
</div>
<div class="editor-label">
<%= Html.LabelFor(model => model.LastName) %>
</div>
<div class="editor-field">
<%= Html.TextBoxFor(model => model.LastName) %>
<%= Html.ValidationMessageFor(model => model.LastName)%>
</div>
<div>
<input type="checkbox" name="selectl" value="ON" id="selectAll"/>
</div>
<p>
<input type="submit" value="Save" />
</p>
控制页
public class HomeController : Controller
{
//
// GET: /Home/
public ActionResult Index()
{
return View();
}
[HttpPost]
public ActionResult Index(HomeModel data)
{
return Content("You submitted: " + data.FirstName + " " + data.LastName);
}
}
模型页面
public class HomeModel
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
此代码的实际输出是在按下按钮时显示在文本框中输入的内容。但是当我选择复选框时,我希望输出如 我在文本框中输入的内容应该是呈现。
请帮帮我朋友。
答案 0 :(得分:0)
ajaxForm
不提交表单。它只是将表单设置为在单击提交按钮时通过ajax提交。
将ajaxForm(options)
更改为ajaxSubmit(options)
。这应该做的伎俩(只是尝试过它,它的工作原理)。