Question

我正在尝试从一个输入字段“上传”多个图像。我将它们移动到我的“上传”目录并将它们的路径保存到我的数据库中。移动部分工作正常，但由于某种原因，它只存储第一个选定图像的路径，并给出警告消息：

mysqli_stmt::bind_param(): Couldn't fetch mysqli_stmt in

代码：

    $filesTempName = $_FILES['images']['tmp_name'];
    $counted = count($filesTempName);
    $maxSize = 2100000;
    $errorMsg = "";

    if ($counted > 5) {
        $errorMsg = "Maximum 5 images!";
    } else {
        for ($i = 0; $i < $counted; $i++) {
            if (empty($filesTempName[$i])) {
                $stmt->execute();
                $stmt->close();
                $link->close();
            } else {
                $allowed_types = array(IMAGETYPE_PNG, IMAGETYPE_JPEG, IMAGETYPE_GIF);
                $detectedType = exif_imagetype($filesTempName[$i]);

                if ($_FILES["images"]["size"][$i] > $maxSize) {
                    $errorMsg = "max 2mb!";
                } elseif (!in_array($detectedType, $allowed_types)) {
                    $errorMsg = "error!";
                } else {
                    $stmt->execute(); //I store other data here, it works fine.
                    $stmt->close();

                    $productid = $link->insert_id;

                    $statement = $link->prepare("INSERT INTO images(thumbnailimage, productid) VALUES(?, ?)");
                    for ($i = 0; $i < $counted; $i++) {
                        $file = $filesTempName[$i];
                        if (is_uploaded_file($file) && !empty($file)) {
                            $data = "uploads/" . time() . $_FILES["images"]["name"][$i];
                            move_uploaded_file($file, $data);
                            $statement->bind_param("si", $data, $productid);
                            $statement->execute(); // I get error for this line
                            $statement->close();
                        }
                    }
                }
            }
        }
    }

这部分抛出错误：

$statement->execute();

Answer 1

从您的代码中删除 ChoiceQuesionListTile( answer: 'Test', onSelected: (value) { print(value); }, ),。您不应手动关闭语句或连接。 $statement->close(); 也是如此。

Answer 2

将 $statement->close(); 移动到 after 循环

$filesTempName = $_FILES['images']['tmp_name'];
$counted = count($filesTempName);
$maxSize = 2100000;
$errorMsg = "";

if ($counted > 5) {
    $errorMsg = "Maximum 5 images!";
} else {
    for ($i = 0; $i < $counted; $i++) {
        if (empty($filesTempName[$i])) {
            $stmt->execute();
            $stmt->close();
            $link->close();
        } else {
            $allowed_types = array(IMAGETYPE_PNG, IMAGETYPE_JPEG, IMAGETYPE_GIF);
            $detectedType = exif_imagetype($filesTempName[$i]);

            if ($_FILES["images"]["size"][$i] > $maxSize) {
                $errorMsg = "max 2mb!";
            } elseif (!in_array($detectedType, $allowed_types)) {
                $errorMsg = "error!";
            } else {
                $stmt->execute(); //I store other data here, it works fine.
                $stmt->close();

                $productid = $link->insert_id;

                $statement = $link->prepare("INSERT INTO images(thumbnailimage, productid) VALUES(?, ?)");
                for ($i = 0; $i < $counted; $i++) {
                    $file = $filesTempName[$i];
                    if (is_uploaded_file($file) && !empty($file)) {
                        $data = "uploads/" . time() . $_FILES["images"]["name"][$i];
                        move_uploaded_file($file, $data);
                        $statement->bind_param("si", $data, $productid);
                        $statement->execute(); // I get error for this line
                        
                    }
                }
                $statement->close();
            }
        }
    }
}

PHP多张图片只上传第一张图片

2 个答案: