Question

我有5张桌子，他们之间有关系。万事如意，完美！但我试图制作脚本，而不是在查询表字段中is_answered = 0，所以我找到受访者（通过问题表中的respondent_id）并发送给他们的信但我有错误！

我有这段代码：

inquiry       = Inquiry.find(:all, :conditions => ["is_answered = 0"])
question      = inquiry.question 
respondents   = Respondent.find(:all, :conditions => ["id = (?)", question.user_id])

respondents.each do |r|
  Notifier.deliver_user_notification(inquiry)
end

当我输入ruby blah.rb时，我收到此错误：

undefined method `question' for #<Array:0x7f646c82b568>

我的错误是什么？

PS - Inquiry表格id, question_id, respondent_i d）questions和answers之间的关系表。 PSS - 与Respondent table相关的Inquiry。

Answer 1

问题是您有更多查询，因此以下内容会返回一个数组。

Inquiry.find(:all, :conditions => ["is_answered = 0"])

尝试以下方法，但要注意它的查询次数，因为可能会进行优化：

inquiry       = Inquiry.find(:all, :conditions => ["is_answered = 0"])
inquiry.each do |i|
    question      = i.question
    respondents   = Respondent.find(:all, :conditions => ["id = (?)", question.user_id])

    respondents.each do |r|
      Notifier.deliver_user_notification(inquiry)
    end
end

有关activerecord的问题

1 个答案: