Question

我开发了一个 Webview 应用程序。在加载 WebView 时，会显示一个作为“进度条”的启动画面。但是我只看到了 1 秒的启动画面，因为在成功加载 webview 后启动画面被隐藏了。加载速度非常快，但我想看到闪屏 3 秒。我怎样才能以启动画面显示 3 秒的方式实现它？

主要活动：


public class MainActivity extends AppCompatActivity {

    String ShowOrHideWebViewInitialUse = "show";
    private WebView webview ;
    private ImageView spinner;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        getDelegate().setDefaultNightMode(AppCompatDelegate.MODE_NIGHT_NO);
        setContentView(R.layout.activity_main);

        webview =(WebView)findViewById(R.id.webView);
        spinner = (ImageView)findViewById(R.id.logo_id3);
        webview.setWebViewClient(new CustomWebViewClient());

        webview.getSettings().setJavaScriptEnabled(true);
        webview.getSettings().setDomStorageEnabled(true);
        webview.setOverScrollMode(WebView.OVER_SCROLL_NEVER);
        webview.loadUrl("xxxxxxxxxx");

    }
    boolean doubleBackToExitPressedOnce = false;

    @Override
    public void onBackPressed() {
        if (webview.canGoBack()){
            webview.goBack();
            Toast.makeText( this, "Going back inside a WebView", Toast.LENGTH_SHORT).show();
        }else {
            this.doubleBackToExitPressedOnce = true;
            Toast.makeText(this, "Doppelt zurück um zu beenden", Toast.LENGTH_SHORT).show();
        }

            if (doubleBackToExitPressedOnce) {
            super.onBackPressed();
            return;
        }



        new Handler(Looper.getMainLooper()).postDelayed(new Runnable() {
            @Override
            public void run() {
                // Your Code
                doubleBackToExitPressedOnce=false;
            }
        }, 2000);
    }

    // This allows for a splash screen
    // (and hide elements once the page loads)
    private class CustomWebViewClient extends WebViewClient {

        @Override
        public void onPageStarted(WebView webview, String url, Bitmap favicon) {

            // only make it invisible the FIRST time the app is run
            if (ShowOrHideWebViewInitialUse.equals("show")) {
                webview.setVisibility(webview.INVISIBLE);
            }
        }

        @Override
        public void onPageFinished(WebView view, String url) {

            ShowOrHideWebViewInitialUse = "hide";
            spinner.setVisibility(View.GONE);

            view.setVisibility(webview.VISIBLE);
            super.onPageFinished(view, url);

        }
    }
}

Answer 1

mWebView.setWebViewClient(new WebViewClient() {

   public void onPageFinished(WebView view, String url) {
        // Hide the splash here 
    }
});

Answer 2

就您而言，您可以通过这种方式延迟代码：

public void onPageFinished(WebView view, String url) {

    Thread.sleep(2000);

    ShowOrHideWebViewInitialUse = "hide";
    spinner.setVisibility(View.GONE);

    view.setVisibility(webview.VISIBLE);
    super.onPageFinished(view, url);

}

2000 的单位是毫秒。所以这将暂停线程 2 秒钟，然后继续

或者像这样使用处理程序类：

public void onPageFinished(WebView view, String url) {

    new Handler().postDelayed(new Runnable() {

        @Override
        public void run() {
            ShowOrHideWebViewInitialUse = "hide";
            spinner.setVisibility(View.GONE);

            view.setVisibility(webview.VISIBLE);
            super.onPageFinished(view, url);

        }
    }, 2000);
}

Answer 3

您可以使用带有 postDelayed 的处理程序

此处 postDelayed 中的代码将在调用 onPageFinished 3 秒后执行

@Override
public void onPageFinished(WebView view, String url) {
    new Handler().postDelayed(new Runnable() {
        @Override
        public void run() {
            ShowOrHideWebViewInitialUse = "hide";
            spinner.setVisibility(View.GONE);

            view.setVisibility(webview.VISIBLE);
            super.onPageFinished(view, url);

        }
    }, 3000); // 3 seconds (3000 millisec)
}

在 onPageFinished 后等待几秒钟

3 个答案: