Question

我不知道我的程序中存在什么问题。运行此选择代码以从我的程序中的SQlite获取数据时，第一次崩溃时出现此错误消息：

杀死目标时杀死错误（无论如何都要杀）：
  警告：函数“macosx_kill_inferior_safe”中的“/SourceCache/gdb/gdb-1510/src/gdb/macosx/macosx-nat-inferior.c”第2179行出错：（os / kern）失败（0x5x）
  退出

这是我的插入代码：

-(id)init {
    self = [super init];

    sqlite3 *database;

    NSMutableArray *locations;
    NSString *result = nil;
    NSString *dbPath = [self getWritableDBPath];

    if(sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) 
    {
        NSString *sqlStr = [NSString stringWithFormat:@"select Longitude,Latitude from myLocation"];
        const char *sqlStatement = [sqlStr UTF8String];
        sqlite3_stmt *compiledStatement;

        if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
            locations = [NSMutableArray array];

            while(sqlite3_step(compiledStatement) == SQLITE_ROW) {

                double longitude = sqlite3_column_double(compiledStatement, 0);
                double latitude = sqlite3_column_double(compiledStatement, 1);
                NSLog(@"%f , %f",longitude,latitude);
                NSString *coords = [[[NSString alloc] initWithFormat:@"%f,%f\n",longitude,latitude] autorelease];

                [locations addObject:coords];
                NSLog(@"this location :-%@",locations);
                //[coords release];

            }

            result = [locations componentsJoinedByString:@","]; // same as `fake_location`
            NSLog(@"this for resulte data :- %@",result);
            // Get file path here

            NSError *error;
            if ( [result writeToFile:dbPath atomically:YES encoding:NSUTF8StringEncoding error:&error] ) {
                NSLog(@"%@", [error localizedDescription]);
            }
        }
        // Release the compiled statement from memory
        sqlite3_finalize(compiledStatement);
    }
    sqlite3_close(database);


    pointsArray = [[result componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] retain];
    pointsArrayIndex = 0;
    oldLocationsIndex = 0;

    [result release];

    oldLocations = [[NSMutableArray alloc] init];


    return self;
}

第二次运行我的应用程序时，它会在控制台上显示我：

保存错误：文件已加密或不是数据库

这些错误意味着什么，我该如何解决？

Answer 1

您需要使用以下命令触发插入查询：

-(void)insertLocation:(double)latitude withLongitude:(double)longitude
{
sqlite3_stmt *insertStatement = nil;
const char *sql = "insert into UserJourneyLocation(Latitude, Longitude) Values(?,?)";
int returnValue = sqlite3_prepare_v2(database, sql, -1, &insertStatement, NULL);
if(returnValue == SQLITE_OK)
{
    sqlite3_bind_double(insertStatement,1,latitude);
            sqlite3_bind_double(insertStatement,2,longitude);
    if(sqlite3_step(insertStatement)==SQLITE_DONE)
    {
        //Data;
    }
}
sqlite3_finalize(insertStatement);
}

Answer 2

是的，我有。

转到iphone应用程序文档文件夹

/ users /（yourname）/ library / application support / iphone simulator / user / application

并删除所有目标。之后重启您的应用程序。

Sqlite数据库文件正在加密或不是数据库

2 个答案: