Question

我有两个像这样的列表

volB = [(Tarp, 3440, 7123), (Greg, 82, 1083)]

和

# 500B = [(Tarp, 85, 203), (Greg, 913, 234)]
B500 = [(Tarp, 85, 203), (Greg, 913, 234)]

我想把第二个元素相互分开。（在这种情况下，我想将3440除以85，将82除以913，依此类推。感谢您的帮助？

Answer 1

from __future__ import division
quotients = [x[1] / y[1] for x, y in zip(list1, list2)]

Answer 2

或者不那么漂亮但是：

lA = [('A',123,11),('B', 1, 11)]
lB = [('B',12,11),('A', 1, 11)]

res = {}

for x,y,z in (lA+lB):
    if not x in res:
        res[x] = y
        continue
    res[x] = res[x] / (y * 1.0)

根据评论编辑为更加pythonic（注意Sven的解决方案已被选为基础）：

from operator import itemgetter

lA = [('A',123,11),('B', 1, 11)]
lB = [('B',12,11),('A', 1, 11)]

[float(x[1])/float(y[1]) for x,y in zip(sorted(lA,key=itemgetter(0)), sorted(lB,key=itemgetter(0)))]

在python中，如何将两个列表列表相互划分？

2 个答案: