public class Talk extends Activity {
private ProgressDialog progDialog;
int typeBar;
TextView text1;
EditText edit;
Button respond;
private String name;
private String textAtView;
private String savedName;
public void onCreate (Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.dorothydialog);
text1 = (TextView)findViewById(R.id.dialog);
edit = (EditText)findViewById(R.id.repsond);
respond = (Button)findViewById(R.id.button01);
respond.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
text1.setText("Welcome! Enter your name!");
respond.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
name = edit.getText().toString();
text1.setText("Cool! your name is "+name);
}
});
}
});
}
}
好的,所以我想知道如何保存这项活动的状态。这只是我代码中的一个小片段,向您展示一个例子。所以我想保存状态,所以当活动被破坏时,用户将返回他们离开的地方 第二件事,我想在每个按钮点击之间显示一个快速的5秒Progress对话框微调器。
答案 0 :(得分:1)
第二件事
这应该有效:
public class TestActivity extends Activity implements Runnable, OnClickListener {
private TextView tv;
private ProgressDialog pd;
private Button btn;
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.main);
tv = (TextView) this.findViewById(R.id.tv);
btn = (Button)findViewById(R.id.btn);
tv.setText("initial text");
btn.setOnClickListener(this);
}
public void onClick(View v) {
pd = ProgressDialog.show(TestActivity.this, "Please wait...", "Details here", true, false);
Thread thread = new Thread(TestActivity.this);
thread.start();
}
public void run() {
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
e.printStackTrace();
}
handler.sendEmptyMessage(0);
}
private Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
pd.dismiss();
tv.setText("text after 5 sec passed");
}
};
}