Question

我的表是这样的：

audit cons articulo  date         bodega  amount    lote
---  |----|-----  |------------|--------|---------|------
11   | 2  | 10    | 04/03/2009 | BMP    | 399     |454
23   | 4  | 11    | 03/03/2009 | BMO    | 244     |787
31   | 2  | 10    | 04/03/2009 | BMP    | 555     |454
45   | 5  | 12    | 03/03/2009 | BNO    | 300     |786
23   | 7  | 11    | 03/03/2009 | BIM1   | 200     |123
61   | 4  | 10    | 04/03/2009 | BIM1   | 500     |783
75   | 5  | 13    | 24/01/2008 | BMP    | 600     |567
75   | 1  | 13    | 24/01/2008 | BMP    | 700     |777

我需要选择每个articulo，bodega和lote的最后日期数量

审计+ cons = pk表

示例：

audit cons articulo  date        bodega  amount      lote
---  |----|-----  |------------|--------|--------- |
11   | 2  | 10    | 04/03/2009 | BMP    | 399      |  454
23   | 4  | 11    | 03/03/2009 | BMO    | 244      |  787
45   | 5  | 12    | 03/03/2009 | BNO    | 300      |  786
23   | 7  | 11    | 03/03/2009 | BIM1   | 200      |  123
61   | 4  | 10    | 04/03/2009 | BIM1   | 500      |  783
75   | 5  | 13    | 01/01/2009 | BMP    | 600      |  567
75   | 1  | 13    | 01/01/2009 | BMP    | 700      |  777

问题在于，当我使用时，我无法获得金额：

select amount, bodega, articulo, max(date) ,lote
 from table 
 group by amount, bodega, articulo,lote

这会重复很多行，任何帮助都会很棒

Answer 1

Oracle 9i +支持ROW_NUMBER：

WITH example AS (
  SELECT t.*,
         ROW_NUMBER() OVER(PARTITION BY t.bodega, t.articulo
                               ORDER BY t.audit) AS rnk
    FROM YOUR_TABLE t)
SELECT e.*
  FROM example e
 WHERE e.rnk = 1

否则，您可以对派生表进行连接（但如果有多个具有相同最高日期值的bodega / articulo，则会返回重复项）：

SELECT a.*
  FROM YOUR_TABLE a
  JOIN (SELECT t.bodega, t.articulo, MAX(t.date) AS maxdate
          FROM YOUR_TABLE t
      GROUP BY t.bodega, t.articulo) b ON b.bodega = a.bodega 
                                      AND b.articulo = a.articulo 
                                      AND b.maxdate = a.date

Answer 2

MIN/MAX using KEEP的组合可能会起作用

Answer 3

SELECT 
  t1.amount, t1.bodega, t1.articulo, t1.date
FROM 
  table t1 join 
  (select 
     bodega, articulo, max(date) date
   from 
     table 
   group by 
     amount, bodega, articulo
  ) on t1.bodega=t2.bodega and t1.articulo=t2.articulo and t1.date=t2.date

Answer 4

试试这个......

select * from table 
where (audit,cons,articulo ,date,bodega,Lote )
in (select min(audit),min(cons),articulo ,max(date),bodega,Lote  
    from table 
    group by articulo , bodega ,lote)

在同一查询中使用max获取一些值

4 个答案: