Question

我的下表中提到了下面提到的值。我有一个标签，显示表格中的日期。第一个日期应显示为07/06/2011，第二个日期应显示如下格式，任何人帮助我..

“标签：07/07/2011至07/13/2011”，

ID  Date                  
==  ==========
63  07/06/2011         
64  07/13/2011         
65  07/20/2011         
66  07/27/2011         
67  08/03/2011

Answer 1

试试这个：

WITH qry AS
(
    SELECT a.*,
           ROW_NUMBER() OVER(ORDER BY Date) rn
      FROM MyTable a
)
SELECT a.Id,
       CASE 
        WHEN b.Id IS NULL THEN CONVERT(VARCHAR, a.Date, 101) 
        ELSE 'Label: ' + 
              CONVERT(VARCHAR, b.Date + 1, 101) + 
              ' to ' + 
              CONVERT(VARCHAR, a.Date , 101) 
       END AS Date
  FROM qry a LEFT JOIN qry b
    ON a.rn  = b.rn+1

表格设置：

CREATE TABLE MyTable (ID INT, DATE DATETIME)
INSERT INTO MyTable VALUES(63,'07/06/2011');
INSERT INTO MyTable VALUES(64,'07/13/2011');
INSERT INTO MyTable VALUES(65,'07/20/2011');
INSERT INTO MyTable VALUES(66,'07/27/2011');
INSERT INTO MyTable VALUES(67,'08/03/2011');

结果：

Id  Date
63  07/06/2011
64  Label: 07/07/2011 to 07/13/2011
65  Label: 07/14/2011 to 07/20/2011
66  Label: 07/21/2011 to 07/27/2011
67  Label: 07/28/2011 to 08/03/2011

Answer 2

根据您的日/月格式，您可以尝试：

SELECT 
CONVERT(VARCHAR, [date] , 4)

以句点格式显示日期

2 个答案: