返回一个静态const []

时间:2011-06-29 13:31:23

标签: iphone objective-c

所以在我的模型中我有以下代码...我成功地能够返回每个单独的值。我想知道我怎么能够返回整个speakerTable [] ...也许有些建议。谢谢!

typedef struct {
    NSUInteger speakerID;
    NSString * speakerName;
    NSString * speakerPosition;
    NSString * speakerCompany;
} SpeakerEntry;

static const SpeakerEntry speakerTable [] = 
{
    {0, @"name", @"position", @"company"},
    {1, @"name", @"position", @"company"},
    {-1, nil, nil, nil}
};

这可以正常工作......

-(NSString *) stringSpeakerCompanyForId:(NSUInteger) identifier{
NSString * returnString = nil;
if ([self helpCount] > identifier) {
    returnString = speakerTable[identifier].speakerCompany;
}
return returnString;

}

这根本不起作用..

-(id) getSpeaker{
//if ([speakerTable[0].speakerName isKindOfClass:[NSString class]])
//  NSLog(@"YES");
NSArray * myArray3 = [NSArray arrayWithArray:speakerTable];
return myArray3;

}

2 个答案:

答案 0 :(得分:6)

arrayWithArray需要一个NSArray,而不是一个C数组。

第一个有效,因为你像C数组一样使用它。

或者 - 不要使用结构,而是使用对象:

创建一个名为Speaker的课程。

在Speaker.h中

@interface Speaker : NSObject {}

@property (nonatomic, assign) NSUinteger id;
@property (nonatomic, copy) NSString name;
@property (nonatomic, copy) NSString position;
@property (nonatomic, copy) NSString company;

- (void)initWithId:(NSUInteger)anId name:(NSString *)aName position:(NSString *)aPosition company:(NSString *)aCompany;

@end
在Speaker.m中

#import "Speaker.h"

@implementation Speaker

@synthesize id, name, position, company;

- (void)initWithId:(NSUInteger)anId name:(NSString *)aName position:(NSString *)aPosition company:(NSString *)aCompany {
    if (!([super init])) {
        return nil;
    }
    id = anId;
    NSString name = [[NSString alloc] initWithString:aName];
    NSString position = [[NSString alloc] initWithString:aPosition];
    NSString company = [[NSString alloc] initWithString:aCompany];

    return self;
}

- (void)dealloc {
    [name release];
    [position release];
    [company release];
    [super dealloc];
}

@end

现在,在您的调用代码中,您可以创建一个不可变的扬声器阵列:

Speaker *speaker0 = [[Speaker alloc] initWithId:0 name:@"name0" position:@"position0" company:@"company0"];
Speaker *speaker1 = [[Speaker alloc] initWithId:1 name:@"name1" position:@"position1" company:@"company1"];
Speaker *speakerNull = [[Speaker alloc] initWithId:-1 name:nil position:nil company:nil];

NSArray *speakerArray [[NSArray arrayWithObjects: speaker0, speaker1, speakerNull] retain]

[speaker0 release];
[speaker1 release];
[speakerNull release];

注意:这是直接输入的,所以随意提及/纠正错别字或错误

答案 1 :(得分:2)

方法arrayWithArray接受NSArray作为参数,而不是C数组。