Question

如何格式化邮件地址，以便始终将所有非空行推送到顶部？也就是说，我想将地址从下面的结构转换为邮寄地址。

这是结构：

[Line1] [varchar](50) NULL,
[Line2] [varchar](50) NULL,
[Line3] [varchar](50) NULL,
[City] [varchar](50) NULL,
[State] [varchar] (2) NULL,
[PostalCode] [varchar](50) NULL,

以下是一些示例数据：

Line1=
Line2=123 Some Address
Line3=
City=Royal Oak
State=MI
ZIP=45673-2312

以下结果应该是（应返回4个不同或单独的字段）：

MailAddress1=123 Some Address
MailAddress2=ROYAL OAK MI 45673-2312
MailAddress3=
MailAddress4=

我正在使用SQL Server 2005。

有人在我们公司写了这个逻辑，它似乎很复杂（注意：这不是整个SELECT语句）：

,CASE 
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN 
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          ELSE eai.Line3
          END
      ELSE eai.Line2
      END
  ELSE eai.Line1
  END
,CASE 
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN
    CASE 
      WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
      ELSE eai.Line3
      END
  ELSE 
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          ELSE eai.Line3
          END
      ELSE eai.Line2
      END
  END
,CASE
  WHEN eai.Line1 IS NULL OR eai.Line1 = '' THEN
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN NULL
      ELSE
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN NULL
          ELSE ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          END
      END 
  ELSE
    CASE 
      WHEN eai.Line2 IS NULL OR eai.Line2 = '' THEN 
        CASE 
          WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN NULL
          ELSE ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
          END
      ELSE 
          CASE 
            WHEN eai.Line3 IS NULL OR eai.Line3 = '' THEN ISNULL(LTRIM(RTRIM(eai.City)),'') + ' ' + ISNULL(LTRIM(RTRIM(eai.RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(eai.PostalCode)),'')
            ELSE eai.Line3
            END
      END
  END
,CASE WHEN eai.Line2 IS NOT NULL AND eai.Line2 <> '' AND eai.Line3 IS NOT NULL AND eai.Line3 <> '' THEN eai.City + ' ' + eai.RegionCode + '  ' + eai.PostalCode ELSE NULL END

Answer 1

这样做的方法是使用UNPIVOT。这是解决方案：

With AddrTable as (
Select AddrFld, MailAddr From (
Select Cast(ISNULL([Line1], '') as Varchar(102)) as [A1], 
       Cast(ISNULL([Line2], '') as Varchar(102)) as [A2], 
       Cast(ISNULL([Line3], '') as Varchar(102)) as [A3], 
       Cast(ISNULL(LTRIM(RTRIM(City)),'') + ' ' + ISNULL(LTRIM(RTRIM(RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(PostalCode)),'') as Varchar(102)) as A4
From TableName Where UniqueID=@UniqueID) p
Unpivot (MailAddr For AddrFld in ([A1], [A2], [A3], [A4])) as unpvt)
Select Row_Number() over (Order by (Case Len(MailAddr) When 0 then 1 else 0 end), AddrFld) as RN, 
MailAddr From AddrTable 
Order By RN

这是输出：

Address1
Westby WI  55555
-empty line-
-empty line-

请注意，我必须使用“Varchar（102）”作为字段长度（unpivot要求所有字段都相同），因为您的城市/地区/邮政总共最多可以有102个字符。另请注意，“@ UniqueID”是您需要的记录的标识符。这将返回四个，总是四个行，其中包含您的地址所需的数据。

更新： 如果您需要将其作为一组四个列而不是四行返回，那么只需将其放入视图中然后使用 Pivot 查询视图。我在这里包含了视图的完整性，因为在创建视图时我必须稍微改变上面的内容，因此包含了uniqueID字段并且没有进行排序（排序现在在查询中完成）：

Create View AddressRows AS
 With AddrTable as (
 Select UniqueID, AddrFld, MailAddr From (
 Select UniqueID, 
       Cast(ISNULL([Line1], '') as Varchar(102)) as [A1], 
       Cast(ISNULL([Line2], '') as Varchar(102)) as [A2], 
       Cast(ISNULL([Line3], '') as Varchar(102)) as [A3], 
       Cast(ISNULL(LTRIM(RTRIM(City)),'') + ' ' + ISNULL(LTRIM(RTRIM(RegionCode)),'') + '  ' + ISNULL(LTRIM(RTRIM(PostalCode)),'') as Varchar(102)) as A4
 From TableName Where UniqueID=@UniqueID) p
 Unpivot (MailAddr For AddrFld in ([A1], [A2], [A3], [A4])) as unpvt)
 Select UniqueID, 
       Row_Number() over (Order by (Case Len(MailAddr) When 0 then 1 else 0 end), AddrFld) as RN, 
       MailAddr From AddrTable

然后，当您想要将匹配的“行”拉出时，使用此SQL将其转回（注意我使用UniqueID再次查询）：

Select [Addr1], [Addr2], [Addr3], [Addr4] From (
Select Top 4 'Addr' + Cast(Row_Number() over (Order by RN) as Varchar(12)) as AddrCol,  -- "Top 4" needed so we can sneak the "Order By" in 
MailAddr 
From AddressRows Where UniqueID=@UniqueID
) p PIVOT (Max([MailAddr]) for AddrCol in ([Addr1], [Addr2], [Addr3], [Addr4])
) as pvt

返回：

Addr1            Addr2                Addr3           Addr4
--------------   ------------------   -------------   ------------------ 
Address1         Westby WI  54667

Answer 2

这是一个三分钟投资的解决方案：

DECLARE @address TABLE (
    [Line1] [varchar](50) NULL,
    [Line2] [varchar](50) NULL,
    [Line3] [varchar](50) NULL,
    [City] [varchar](50) NULL,
    [State] [varchar] (2) NULL,
    [PostalCode] [varchar](50) NULL
)

INSERT INTO @address (
    [Line1],
    [Line2],
    [Line3],
    [City],
    [State],
    [PostalCode]
)
VALUES (
    NULL,
    '123 Some Address',
    NULL,
    'Royal Oak',
    'MI',
    '45673-2312'
)

SELECT * FROM @address

SELECT
      ISNULL(Line1 + CHAR(13), '')
    + ISNULL(Line2 + CHAR(13), '')
    + ISNULL(Line3 + CHAR(13), '')
    + ISNULL(City    + ' ',    '')
    + ISNULL([State] + ' ',    '')
    + ISNULL(PostalCode,       '')
FROM @address

结果：

123 Some Address
Royal Oak MI 45673-2312

在获得所需结果之前，先控制控制字符。

Answer 3



SELECT 
    LTRIM(RTRIM(LINE1)) + LTRIM(RTRIM(LINE2)) + LTRIM(RTRIM(LINE3)) AS MailAddress1,
    LTRIM(RTRIM(CITY)) + ' ' + LTRIM(RTRIM(STATE)) + ' ' + LTRIM(RTRIM(POSTALCODE)) AS MailAddress2
FROM MyTable

如何改进此邮件地址SQL Server SELECT语句？

3 个答案: