Question

我需要将以下内容转换为链接：

＆LT;一个 HREF =“http://maps.google.com/maps?um=1&ie=UTF-8&q=little+river+canyon+center&fb=1&gl=us&hq=little+river+canyon + center＆amp; hnear = 0x888a614b2e7272e5％3A0x913a5fafeec714d6％2CCentre％2C + AL＆amp; ei = GBsFTtedF8vUgAfex6zNAQ＆amp; sa = X＆amp; oi = local_group＆amp; ct = image＆amp; ved = 0CAQQtgM＆lt; br“target =”_ blank“＆gt; http：// maps。 google.com/maps?um=1&ie=UTF-8&q=little+river+canyon+center&fb=1&gl=us&hq=little+river+canyon+center&hnear=0x888a614b2e7272e5%3A0x913a5fafeec714d6% 2CCentre％2C + AL＆安培; EI = GBsFTtedF8vUgAfex6zNAQ＆安培; SA = X＆安培; OI = local_group＆安培; CT =图像＆安培; VED = 0CAQQtgM＆LT峰; br＆LT; / A＆GT; /＆GT;

这是我目前使用的正则表达式不起作用：

$hike_description = preg_replace('#([\s|^])(www)#i', '$1http://$2', $hike_description);
$pattern = '#((http|https|ftp|telnet|news|gopher|file|wais):\/\/[^<\s]+)#i';
$replacement = '<a href="$1" target="_blank">$1</a>';
$hike_description = preg_replace($pattern, $replacement, $hike_description);

远足描述是我需要在链接中创建的文本。

Answer 1

首先尝试修剪“/＆gt;”

 $hike_description="http://maps.google.com/maps?um=1&ie=UTF-8&q=little+river+canyon+center&fb=1&gl=us&hq=little+river+canyon+center&hnear=0x888a614b2e7272e5%3A0x913a5fafeec714d6%2CCentre%2C+AL&ei=GBsFTtedF8vUgAfex6zNAQ&sa=X&oi=local_group&ct=image&ved=0CAQQtgM />";

$hike_description =trim($hike_description,"/>");


$hike_description = preg_replace('#([\s|^])(www)#i', '$1http://$2', $hike_description);
$pattern = '#((http|https|ftp|telnet|news|gopher|file|wais):\/\/[^<\s]+)#i';

$replacement = '<a href="$1" target="_blank">$1</a>';
$hike_description = preg_replace($pattern, $replacement, $hike_description);

Answer 2

在编辑过的问题中，这已经不是很清楚了，但是从最初的问题来看，我猜这里的整个问题是链接以<br结尾，这在HTML中是不合法的。

尝试在$ hike_description上使用htmlspecialchars。

需要帮助来提出正则表达式将其转换为链接

2 个答案: