对象不可迭代

时间:2011-06-29 01:36:37

标签: django django-templates

我遇到了一个奇怪的问题......这段代码工作正常,直到我处理了其他一些观点,现在,它无法正常工作。

以下是我的观点:

def showTickets(request, project_slug):
    project = Project.objects.get(slug=project_slug)
    tickets = Ticket.objects.get(project=project)
    payload = { 'project':project, 'tickets':tickets}
    return render(request, 'project/tickets.html', payload)

模板:

{% extends 'project/base.html' %}

{% block title %}Tickets: {{project.name}}{% endblock %}

{% block main %}

<div id="project-nav">
    <span><a href="/project/{{project.slug}}/">Tickets</a></span>
    <span><a href="/book/{{book.slug}}{{book.name}}">Docs</a></span>
    <span><a href="/project/{{project.slug}}/browse">Browser</a></span>
</div>
<div id="action-nav">
    {% block actions %}
    <span><a href="/project/{{project.slug}}/tickets/create">Create Ticket</a></span>
    <span><a href="/project/{{ project.slug }}/tickets/recent/">Recent Activity</a></span>
    <span><a href="/project/{{ project.slug }}/tickets/my/">My Tickets</a></span>
    {% endblock %}
</div>
{% for ticket in tickets %}


<div class="ticket">
    <div class="ticket-header">
        <div class="ticket-title">
            <a href="/project/ticket/{{ticket.pk}}">{{ticket.subject}}</a>
        </div>
        <div id="ticket-number">
            #{{ticket.pk}}
        </div>
        <div id="ticket-state">
            {{ticket.get_state_display}}
        </div>
        <div id="ticket-info">
            Reported by {{ticket.created_by}} | created: {{ticket.created_on }} | modified: {{ticket.modified_on}}
        </div>
    </div>
</div>
{% endfor %}
</div>

{% endblock %}

错误:

Template error:
In template c:........\project\tickets.html, error at line 19
   Caught TypeError while rendering: 'Ticket' object is not iterable

这工作正常,直到我处理其他一些观点...不确定为什么它现在不起作用?如果任何人可以帮助我,我会很感激!

2 个答案:

答案 0 :(得分:7)

project = Project.objects.get(slug=project_slug) 
tickets = Ticket.objects.get(project=project) 

这两行是导致你烦恼的原因。它们不返回可迭代的(如列表),而是返回一个根本不可迭代的对象。而不是get,而是使用过滤器,它将返回一个列表。

答案 1 :(得分:3)

get()方法返回单个对象。也许您打算使用filter()方法?