我有一个mysqli查询,代码如下:
$db_usag->query("UPDATE Applicant SET phone_number ='$phone_number', street_name='$street_name', city='$city', county='$county', zip_code='$zip_code', day_date='$day_date', month_date='$month_date', year_date='$year_date' WHERE account_id='$account_id'");
但是所有数据都是从HTML文档中提取的,所以为了避免错误,我想使用预处理语句。我找到了PHP文档,但没有UPDATE示例
答案 0 :(得分:61)
UPDATE
的作用与插入或选择相同。只需用?
替换所有变量。
$sql = "UPDATE Applicant SET phone_number=?, street_name=?, city=?, county=?, zip_code=?, day_date=?, month_date=?, year_date=? WHERE account_id=?";
$stmt = $db_usag->prepare($sql);
// This assumes the date and account_id parameters are integers `d` and the rest are strings `s`
// So that's 5 consecutive string params and then 4 integer params
$stmt->bind_param('sssssdddd', $phone_number, $street_name, $city, $county, $zip_code, $day_date, $month_date, $year_date, $account_id);
$stmt->execute();
if ($stmt->error) {
echo "FAILURE!!! " . $stmt->error;
}
else echo "Updated {$stmt->affected_rows} rows";
$stmt->close();