这给了我一个错误:
<!--
To change this template, choose Tools | Templates
and open the template in the editor.
-->
<!DOCTYPE html>
<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script type="text/javascript">
function loadXMLDoc(dname)
{
if (window.XMLHttpRequest)
{
xhttp=new XMLHttpRequest();
}
else
{
xhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xhttp.open("GET",dname,false);
xhttp.send();
return xhttp.responseXML;
}
var xmlDoc=loadXMLDoc("books.xml");
var books = xmlDoc.getElementByTagName("title");
for(var i = 0; i < books.length; i++){
document.write(xmlDoc.getElementsByTagName("title")[i].childNodes[0].nodeValue + "<br />");
document.write(xmlDoc.getElementsByTagName("author")[i].childNodes[0].nodeValue + "<br />");
document.write(xmlDoc.getElementsByTagName("year")[i].childNodes[0].nodeValue + "<br />");
}
</script>
</head>
<body>
<div>TODO write content</div>
</body>
</html>
但是,如果我删除该行:var books = xmlDoc.getElementByTagName("title");
并将books.length
替换为'3'
则可以。
我的XML:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!-- Edited by XMLSpy® -->
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web" cover="paperback">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>
答案 0 :(得分:3)
可能只是你在xmlDoc.getElementsByTagName(“title”)中省略了“s”?
答案 1 :(得分:1)
使用XPath
表达式而不是getElementsByTagName:
var x=loadXMLDoc("books.xml");
var xml=x.responseXML;`<br/>
path="/bookstore/book/title";
var nodes=xml.evaluate(path, xml, null, XPathResult.ANY_TYPE, null);
var result=nodes.iterateNext();
while (result)
{
document.write(result.childNodes[0].nodeValue);
document.write("<br>");
result=nodes.iterateNext();
}
我很难格式化代码:(