Question

我将图像转换为数据并将图像保存在数据库中如下所示 NSData * imageData = UIImagePNGRepresentation（imgView.image）;

[dataArray addObject:imageData];

并按照

将数据检索到图像中

        NSData *imdata = [[tableArray objectAtIndex:indexPath.row] objectForKey:@"Image"];

SQlite保存代码：

   if (sqlite3_open([databasePath UTF8String], &database)== SQLITE_OK)
    {
        NSString *statement;
        sqlite3_stmt *compiledstatement;
        int Id;
        NSString *Name;
        NSData *imgData;



        Id = [[recordArray objectAtIndex:0] intValue];
        Name = [recordArray objectAtIndex:1];

        imgData = [recordArray objectAtIndex:2];
        statement = [[NSString alloc]initWithFormat:@"insert into ImageTable values ('%d','%@','%@')",Id,Name,imgData] ;
        const char *sqlstatement = [statement UTF8String];

        if (sqlite3_prepare_v2(database, sqlstatement, -1, &compiledstatement, NULL)== SQLITE_OK) {
            if (SQLITE_DONE!=sqlite3_step(compiledstatement) ) {
                NSAssert1(0,@"Error when inserting  %s",sqlite3_errmsg(database));
            }
            else {

                NSLog(@"Data inserted Successfully");
            }
            //[recordDict release];
        }
        else {
            NSLog(@"Failed with error");
            NSAssert1(0,@"Error when creation %s",sqlite3_errmsg(database));

        }



    }
    //sqlite3_finalize(compiledstatement);

Sqlite代码获取：

  - (NSMutableArray *) getRecord
     {
[self checkAndCreateDatabase];

sqlArray=[[NSMutableArray alloc]init ];


if (sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK)
{
    const char *sql = "select * from ImageTable";
    sqlite3_stmt *selectstmt;
    if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) 
    {
        while(sqlite3_step(selectstmt) == SQLITE_ROW)
        {
            //[sqlDict retain];
            sqlDict =[[NSMutableDictionary alloc]init ];

            NSString *Id = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 0)];
            //[barcodeArray addObject:prdbcode];
            [sqlDict setObject:Id forKey:@"Id"];
            //[prdbcode release];


            NSString *name = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)];
            //[nameArray addObject:prdname];
            [sqlDict setObject:name forKey:@"Name"];
            //[prdname release];


            NSData *image = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 2)];
            //NSData *data = [[NSData alloc] initWithBytes:sqlite3_column_blob(selectstmt, 1) length:sqlite3_column_bytes(selectstmt, 1)];              
            //[descArray addObject:prdDesc];
            [sqlDict setObject:image forKey:@"Image"];
            // [prdDesc release];
            [sqlArray addObject:sqlDict];
        }


        sqlite3_finalize(selectstmt);   

    }

    sqlite3_close(database);
    //  
}

return sqlArray;

}

[imView setImage:[UIImage imageWithData:imdata]];
[cell addSubview:imView];

ID和名称被检索但图像没有显示。应用程序终止，没有任何错误消息.. 请让我知道解决方案

Answer 1

我知道我的答案为时已晚，但对于那些查看此问题的人来说可能会有用，通常是在使用BLOB在sqlite数据库表中编写图像时，会对数据库的性能产生影响并会减慢速度数据的加载，当记录开始增加数量。没有使用BLOB，你可以保存和检索数据库中的图像，这里是post/link，将帮助你继续进行和完成任务

希望它可以帮助那些被数据库中的图像存储感染的人:)

Answer 2

我没有看到任何sqlite数据库代码。如果您只是想从dataArray中提取图像，则需要：

NSData *imdata = [dataArray objectAtIndex:indexPath.row];

如何从Sqlite数据库保存和检索图像？

2 个答案: