Question

我需要为跨域脚本创建一个php代理。我为此问题从Web检索脚本。当我尝试加载本地页面时，我的php代码运行良好，但是当我尝试加载像www.google.it这样的外部页面时，我的代理不起作用。

我想知道我是否必须在我的服务器网站（Apache）上设置一些东西，以使代理工作正常。

提前致谢。

编辑：这是我的代码。我在网上找到了它。

<?php
//          FILE: proxy.php
//
// LAST MODIFIED: 2006-03-23
//
//        AUTHOR: Troy Wolf <troy@troywolf.com>
//
//   DESCRIPTION: Allow scripts to request content they otherwise may not be
//                able to. For example, AJAX (XmlHttpRequest) requests from a
//                client script are only allowed to make requests to the same
//                host that the script is served from. This is to prevent
//                "cross-domain" scripting. With proxy.php, the javascript
//                client can pass the requested URL in and get back the
//                response from the external server.
//
//         USAGE: "proxy_url" required parameter. For example:
//                http://www.mydomain.com/proxy.php?proxy_url=http://www.yahoo.com
//

// proxy.php requires Troy's class_http. http://www.troywolf.com/articles
// Alter the path according to your environment.
require_once("class_http.php");

$proxy_url = isset($_GET['proxy_url'])?$_GET['proxy_url']:false;
//echo "-1";
if (!$proxy_url) {
    header("HTTP/1.0 400 Bad Request");
    echo "proxy.php failed because proxy_url parameter is missing";
    exit();
}
//echo "0";
// Instantiate the http object used to make the web requests.
// More info about this object at www.troywolf.com/articles
if (!$h = new http()) {
    header("HTTP/1.0 501 Script Error");
    echo "proxy.php failed trying to initialize the http object";
    exit();
}

$h->url = $proxy_url;
/*$h->postvars = $_POST;*/
if (!$h->fetch($h->url)) {
    header("HTTP/1.0 501 Script Error");
    echo "proxy.php had an error attempting to query the url";
    exit();
}

// Forward the headers to the client.
$ary_headers = split("\n", $h->header);
foreach($ary_headers as $hdr) { header($hdr); }

// Send the response body to the client.
echo $h->body;

?>

如何设置apache来创建php代理

0 个答案: