Question

看，我有这片XSD：

<xs:complexType name="ResourcesType">
    <xs:sequence>
      <xs:element name="Classrooms">
        <xs:complexType mixed="true">
          <xs:sequence>
            <xs:element type="ResourceType" name="Resource" maxOccurs="unbounded" minOccurs="0"/>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
      <xs:element name="Teachers">
        <xs:complexType mixed="true">
          <xs:sequence>
            <xs:element type="ResourceType" name="Resource" maxOccurs="unbounded" minOccurs="0"/>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
      <xs:element name="Classes">
        <xs:complexType mixed="true">
          <xs:sequence>
            <xs:element type="ResourceType" name="Resource" maxOccurs="unbounded" minOccurs="0"/>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
      <xs:element name="Special">
        <xs:simpleType>
          <xs:restriction base="xs:string">
            <xs:enumeration value="0"/>
            <xs:enumeration value=""/>
          </xs:restriction>
        </xs:simpleType>
      </xs:element>
    </xs:sequence>
  </xs:complexType>

我使用eclipse插件从模式生成了类，我得到了这个：

带有ResourcesType，Classes和ClassRooms内部课程的

Teachers课程。在所有这些内部类中，我保护了List<Serializable>内容字段。它还生成ClassesType，ClassRoomsType和TeachersType作为普通类。

为什么生成这个内部类？如果其他类不可序列化，我将如何设置此List？

谢谢你最好的问候

Answer 1

为什么生成了这个内部类？

JAXB实现将是匿名复杂类型的内部类。这样做是为了减少生成的类的名称冲突的可能性。

<xs:complexType name="ResourcesType">
    <xs:sequence>
      <xs:element name="Classrooms">
        <xs:complexType mixed="true">
          <xs:sequence>
            <xs:element type="ResourceType" name="Resource" maxOccurs="unbounded" minOccurs="0"/>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
      ...
    </xs:sequence>

    </xs:complexType>

<小时/>

如果另一个我如何设置此列表类不可序列化？

content属性的允许内容为JAXBElement<ResourceType>和String。 Serializable是这两种类型的通用接口，比Object更具限制性。

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "content"
})
public static class Classes {

    @XmlElementRef(name = "Resource", type = JAXBElement.class)
    @XmlMixed
    protected List<Serializable> content;

    /**
     * Gets the value of the content property.
     * 
     * <p>
     * This accessor method returns a reference to the live list,
     * not a snapshot. Therefore any modification you make to the
     * returned list will be present inside the JAXB object.
     * This is why there is not a <CODE>set</CODE> method for the content property.
     * 
     * <p>
     * For example, to add a new item, do as follows:
     * <pre>
     *    getContent().add(newItem);
     * </pre>
     * 
     * 
     * <p>
     * Objects of the following type(s) are allowed in the list
     * {@link JAXBElement }{@code <}{@link ResourceType }{@code >}
     * {@link String }
     * 
     * 
     */
    public List<Serializable> getContent() {
        if (content == null) {
            content = new ArrayList<Serializable>();
        }
        return this.content;
    }

}

<强>更新

以下示例可能有所帮助：

package example;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.Marshaller;
import javax.xml.namespace.QName;

import example.ResourcesType.Classrooms;

public class Demo {

    public static void main(String[] args) throws Exception {
        // This is the ObjectFactory that was generated by XJC
        ObjectFactory objectFactory = new ObjectFactory();

        // You can instantiate objects using the constructors
        ResourcesType resourcesType = new ResourcesType();

        // You can instantiate objects using the ObjectFactory
        Classrooms classRooms = objectFactory.createResourcesTypeClassrooms();
        resourcesType.setClassrooms(classRooms);

        // You can use the ObjectFactory to wrap an object in a JAXBElement
        ResourceType resourceType1 = new ResourceType();
        JAXBElement<ResourceType> jaxbElement1 = objectFactory.createResourcesTypeClassesResource(resourceType1);
        classRooms.getContent().add(jaxbElement1);

        ResourceType resourceType2 = objectFactory.createResourceType();
        JAXBElement<ResourceType> jaxbElement2 = objectFactory.createResourcesTypeClassesResource(resourceType2);
        classRooms.getContent().add(jaxbElement2);

        // You can create a JAXBContext on the package name of your generated classes
        JAXBContext jc = JAXBContext.newInstance("example");

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

        // You can also create an instance of JAXBElement without using the ObjectFactory
        JAXBElement<ResourcesType> rootElement = new JAXBElement<ResourcesType>(new QName("root"), ResourcesType.class, resourcesType);
        marshaller.marshal(rootElement, System.out);
    }

}

Jaxb应该编组内部类吗？

1 个答案: