Question

使用 Google Closure库：

如何处理点击element例如div，但阻止在用户点击该元素的子元素时触发event handler。

例如，在以下代码中，我想在用户点击event handler时触发div1但是当他/她点击“span1”时，我希望调用另一个event handler而不触发div1的处理程序。

<div style="width: 400px" id="div1">
 <span id="span1">click me to reload</span>
 click here to Toggle accordion
</div>

更新

JS代码：

/**** accordion ***/
var panels = goog.dom.getElementsByClass('newsColumnHeader', goog.dom.getElement('accordionContainer'));

var anims  = {};
var open   = null;

goog.array.forEach(panels, function(pane){
  var animation = new goog.ui.AnimatedZippy(pane, goog.dom.getNextElementSibling(pane));
  goog.events.listen(animation, goog.ui.Zippy.Events.TOGGLE, zippyToggle);
  anims[goog.getUid(animation)] = animation;
});

function zippyToggle(event) {      
  var uid = goog.getUid(event.target);                  
  // simple logic - only one open panel in one time
  if (event.expanded && uid != open) {
    if (open) {
      anims[open].setExpanded(false);
    }
    open = uid;
  }
}
/******************/           

var refreshVarzesh3 = goog.dom.getElement("btnRefreshVarzesh3");
if (refreshVarzesh3 != null) {
  goog.events.listen(refreshVarzesh3, goog.events.EventType.CLICK, function(event) {
    /*doing something but not toggling accordion pane*/
  });
}

HTML CODE：

  <body>
<div class="main">
  <div class="top">
    <div id="toolbar">          
      <img src="css/img/contact.png" alt="تماس، پیشنهاد، گزارش خطا" title="تماس، پیشنهاد، گزارش خطا"/>          
    </div>
    <img src="css/img/football_news.gif" alt="آخرین اخبار فوتبال"/>
  </div>
  <div class="middle">
    <div class="left"></div>
    <div class="right">
      <div class="accordion" id="accordionContainer">
        <div class="newsColumnHeader">
          <div class="buttons">
            <img id="btnRefreshVarzesh3" src="css/img/refresh.png" alt="به روز رسانی" title="به روز رسانی"/>                
          </div>
          <%=lbls.getString("Varzesh3News")%>
        </div>
        <div class="newsList" id="varzesh3NewsContainer"></div>
        <div class="newsColumnHeader"><%=lbls.getString("PersepolisNews")%></div>
        <div class="newsList" id="persepolisNewsContainer"></div>
        <div class="newsColumnHeader"><%=lbls.getString("EsteghlalNews")%></div>
        <div class="newsList" id="esteghlalNewsContainer"></div>
        <div class="newsColumnHeader"><%=lbls.getString("NavadNews")%></div>
        <div class="newsList" id="navadNewsContainer"></div>
      </div>
    </div>
  </div>
  <div class="bottom"></div>
</div>

Answer 1

对于纯javascript 开发人员，答案是here，但如果您使用 Google Closure Library ，则以下代码就足够了：

event.stopPropagation();

Answer 2

在该点击的事件处理程序中，您必须使用preventDefault（）

例如：

document.getElementById('div1').onclick = function (event) {
   //your code
   event.preventDefault();
}

Answer 3

您应该阅读此链接以了解有关活动的更多信息 http://www.quirksmode.org/js/events_order.html

Answer 4

仅供参考Google Closure中的所有事件均来自goog.events.Event

http://docs.closure-library.googlecode.com/git/class_goog_events_Event.html

例如：goog.events.BrowserEvents

所以第一个一个是stopPropagation

 this.getHandler().listen(element ,goog.events.EventType.CLICK, function (e){
    e.stopPropagation();
  });

第二一个是goog.events.Event.stopPropagation是静态方法反过来调用上面的方法

goog.events.Event.stopPropagation = function(e) {
  e.stopPropagation();
};

编辑：请阅读 - Dangers of Event Propagation

使用Google Closure Library阻止事件传播

4 个答案: