熊猫差异比较

Question

我有这段代码，我正试图颠倒该过程，以使A列不同后在B3和C3中获得相同的值。

df = pd.DataFrame({'A': np.random.randint(0, 10, 10)})
df['C'] = df['A']
df['B'] = df['A'].diff(periods=1)

df['B2'] = df['B'].shift(-2)
df['B3'] = np.where(df['B2'] > df['B'], 1, -1)

df['C2'] = df['C'].shift(-2)
df['C3'] = np.where(df['C2'] > df['C'], 1, -1)

这是结果：

   A  C    B   B2  B3   C2  C3
0  4  4  NaN -7.0  -1  1.0  -1
1  8  8  4.0  5.0   1  6.0  -1
2  1  1 -7.0 -3.0   1  3.0   1
3  6  6  5.0 -2.0  -1  1.0  -1
4  3  3 -3.0  6.0   1  7.0   1
5  1  1 -2.0 -4.0  -1  3.0   1
6  7  7  6.0  0.0  -1  3.0  -1
7  3  3 -4.0  1.0   1  4.0   1
8  3  3  0.0  NaN  -1  NaN  -1
9  4  4  1.0  NaN  -1  NaN  -1

我将如何反转差分的B3列以获得与C3相同的值？