Question

这是我的路线

Route::get("experience",[experienceController::class,'experience'])->name('experience');
Route::get("add_experience",[experienceController::class,'add_experience'])->name('add_experience');
Route::post("store_experience",[experienceController::class,'store_experience'])->name('store_experience');
Route::get("all_experience",[experienceController::class,'all_experience'])->name('all_experience');
Route::get('view/experience/{id}',[experienceController::class,'view_experience']);
Route::get('delete_experience/{id}',[experienceController::class,'delete_experience']);
Route::get('edit_experience/{id}',[experienceController::class,'delete_experience']);

这是我的网址：

<td>
  <a href="{{URL::to('edit_experience'.$row->id)}}" class="btn btn-sm btn-info">Edit</a>
  <a href="{{URL::to('delete_experience'.$row->id)}}" class="btn btn-sm btn-danger">Delete</a>
  <a href="{{URL::to('view_experience/'.$row->id)}}" class="btn btn-sm btn-success">View</a>
</td>

Answer 1

尝试：

<td>
  <a href="{{URL::to('edit_experience/'.$row->id)}}" class="btn btn-sm btn-info">Edit</a>
  <a href="{{URL::to('delete_experience/'.$row->id)}}" class="btn btn-sm btn-danger">Delete</a>
  <a href="{{URL::to('view_experience/'.$row->id)}}" class="btn btn-sm btn-success">View</a>
</td>

而且，在您的情况下，我可以看到您拥有完整的CRUD结构，因此您可以考虑使用资源路由(see laravel documentation)，并将创建索引，显示，创建，存储，编辑，更新和销毁所有带有名称的路线。

另一方面，我建议使用route（'name'）函数，我认为这更好，因为在路由更改的情况下，不要修改所有网站。

好运，埃尔南。

已路由已定义，但显示404未找到

1 个答案: