我有一个列表对象,我想递归地迭代直到找到具有“主机名”值的“节点”并通过其代码计数状态。 问题是我可以在彼此内部随机地有多个“节点”。
免责声明:我不是开发人员,只是一个发烧友,所以请放心! :)
我已经尝试过一堆循环(例如,一会儿等等)来调用一些函数来验证节点的内容,但是当我彼此之间有多个节点时,这会使我失败。
任何帮助将不胜感激, 干杯,
[
u"MY CONTAINER",
u"MY APP",
"0",
"",
{
"title": u"MyApp",
"state": 0,
"nodes": [
{
"title": u"AppStuff01",
"state": 0,
"nodes": [
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
],
"currently_active": True,
},
{
"title": u"AppStuff02",
"state": 0,
"nodes": [
{
"title": u"MySubApp",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
"nodes": [
{
"title": u"Another Random Node",
"state": 0
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
},
],
],
"currently_active": True,
}
],
"currently_active": True,
},
],
"currently_active": True,
},
"0",
"0",
]
答案 0 :(得分:1)
您可以递归检查列表,以查找具有nodes
属性的hostname
:
(PS:您的原始列表中有一些我必须修复的语法错误)
如果您的列表是这样的变量:
my_list = [
u"MY CONTAINER",
u"MY APP",
"0",
"",
{
"title": u"MyApp",
"state": 0,
"nodes": [
{
"title": u"AppStuff01",
"state": 0,
"nodes": [
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
],
"currently_active": True,
},
{
"title": u"AppStuff02",
"state": 0,
"nodes": [
{
"title": u"MySubApp",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"Another Random Node",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
},
],
},
],
"currently_active": True,
}
],
"currently_active": True,
},
],
"currently_active": True,
},
"0",
"0",
]
然后您可以使用如下函数:
def find_nodes(to_check):
nodes = []
if type(to_check).__name__ != "list":
return nodes
for element in to_check:
if type(element).__name__ == "dict":
if "hostname" in element:
nodes.append(element)
if "nodes" in element:
nodes.extend(find_nodes(element["nodes"]))
return nodes
print(find_nodes(my_list))