我有一个数据框:
Type value1 value2
1 Error: unexpected seq warn
2 Warning message excepted action
3 NA produce values
4 In `[<-.factor`(`*tmp*`, iseq, value = "v1") values produced
5 NA rewriting data
我想用列value2中的值填充列value1中的NA。我该怎么写条件?所需的结果是:
Type value1 value2
1 Error: unexpected seq warn
2 Warning message excepted action
3 produce values produce values
4 In `[<-.factor`(`*tmp*`, iseq, value = "v1") values produced
5 rewriting data rewriting data
答案 0 :(得分:1)
您可以使用coalesce
:
library(dplyr)
df %>% mutate(value1 = coalesce(value1, value2))
或者在基数R中:
transform(df, value1 = ifelse(is.na(value1), value2, value2))
答案 1 :(得分:1)
我们可以使用string jsonrpc
中的 var responseBody = await response.Content.ReadAsByteArrayAsync().ConfigureAwait(false);
using Stream ms = new MemoryStream(responseBody);
var serializationOptions = new JsonSerializerOptions()
{
IgnoreNullValues = true,
Encoder = JavaScriptEncoder.UnsafeRelaxedJsonEscaping,
};
LanguagesResponse responseObject = await JsonSerializer.DeserializeAsync<LanguagesResponse>(ms, serializationOptions, token).ConfigureAwait(false);
fcoalesce