Question

我与一个支点有很多关系

旅游模式

public function teams()
    {
        return $this->belongsToMany('App\Models\APP\Team\Team', 'team_tourney')->withPivot('status')->withTimestamps();
    }

团队模型


public function tourneys()
    {
        return $this->belongsToMany('App\Models\APP\Tourney\Tourney', 'team_tourney')->withPivot('status')->withTimestamps();
    }

用户模型

public function tourneys()
    {
        return $this->hasMany('App\Models\APP\Tourney\Tourney');
    }

public function teams()
    {
        return $this->hasMany('App\Models\APP\Team\Team');
    }

控制器显示功能：

$tourney = Tourney::with('user', 'teams')->where('slug', $slug)->first();

$teams = Team::with('tourneys')->where('user_id', auth()->user()->id)->get();

在我看来，我需要首先获取用户团队的列表。然后检查Tourney团队是否包含任何一个用户团队并列出他们。

@foreach($teams as $team)
  {{-- List teams if already attached --}}
  @if($tourney->teams->contains($team))

     {{-- Get TourneyTeam status --}}
     @foreach($tourney->teams as $tourneyTeam)
        <p>{{$tourneyTeam->pivot->status}}</p>
     @endforeach

                           
   @endif
@endforeach

这样做时，我将状态打印两次。例如，返回11而不是1

我认为这是因为我在一个循环中有一个循环。如何调整为仅返回一次状态。

Answer 1

我能够通过创建另一个查询并将其添加为刀片导数来解决此问题。

刀片衍生物

Blade::if('teamTourneyStatus', function($tourney, $team){
            
     $team = $tourney->teams->where('id', $team->id)->first();
        if($team->pivot->status == 1){
            return true;
        }
            return false;
                       
});

更新后的视图

@foreach($teams as $team)
  {{-- List teams if already attached --}}
  @if($tourney->teams->contains($team))

     {{-- Get TourneyTeam status --}}
     @teamTourneyStatus($tourney, $team) "show if true" @endteamTourneyStatus
                   
   @endif
@endforeach

Larvel foreach带枢轴

1 个答案: