Question

我想得到一个在一个过程（b）中分配的列表，并将其作为OUT参数返回到过程（a）中的'table of varchar2'变量。如何定义OUT参数类型？

例）

procedure_a()
type t_list IS TABLE OF VARCHAR2(10)

l_list t_list;

procedure_b(l_list);

end procedure_a;

procedure_b(out_list OUT ????)

OUT类型是什么？

提前致谢。

Answer 1

需要在A和B都可以引用的某个地方声明类型。一种选择是在包中声明类型，即

SQL> create package some_pkg
  2  as
  3    type t_list is table of varchar2(10);
  4
  5    procedure procedureA;
  6    procedure procedureB( p_list OUT t_list );
  7  end;
  8
  9  /

Package created.

SQL> create or replace package body some_pkg
  2  as
  3    procedure procedureA
  4    as
  5      l_list t_list;
  6    begin
  7      procedureB( l_list );
  8      dbms_output.put_line( l_list.count );
  9    end;
 10
 11    procedure procedureB
 12      ( p_list OUT t_list )
 13    as
 14    begin
 15      select ename
 16        bulk collect into p_list
 17        from emp;
 18    end;
 19  end;
 20  /

Package body created.

SQL> exec some_pkg.procedureA;
16

PL/SQL procedure successfully completed.

另一种选择是在SQL中声明类型，即

SQL> create type t_list
  2      as table of varchar2(10);
  3  /

Type created.

SQL> ed
Wrote file afiedt.buf

  1  create or replace procedure procedureB( p_list OUT t_list )
  2  as
  3  begin
  4    select ename
  5      bulk collect into p_list
  6      from emp;
  7* end;
SQL> /

Procedure created.

SQL> create or replace procedure procedureA
  2  as
  3    l_list t_list;
  4  begin
  5    procedureB( l_list );
  6    dbms_output.put_line( l_list.count );
  7  end;
  8  /

Procedure created.

SQL> exec procedureA;
16

PL/SQL procedure successfully completed.

Oracle程序'out''表varchar2'类型参数

1 个答案: