Question

假设我有两个这样的列表，

Ii = [[7,1],[7,5],[7,8],[5,8],[2,8],[3,5]]
ci = [11,5,3,5,5,4]

现在，我要列出另一个m x n的列表（I），它看起来像这样，

I = 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[11, 0, 0, 0, 5, 0, 0, 3, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 4, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

我尝试了这段代码，

m,n = 8,10    
I = [[0 for j in range(n)] for i in range(m)]
    for i, j in Ii:
        I[m - i][j - 1] = 1

哪个输出看起来像这样

I = 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[1, 0, 0, 0, 1, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 1, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 1, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

现在我有1个想要ci值的位置。但是我想将ci的值放在1的位置。需要有关如何执行此操作的帮助吗？

Answer 1

m = 8 
n = 10 
Ii = [[7,1],[7,5],[7,8],[5,8],[2,8],[3,5]]
ci = [11,5,3,5,5,4]

I = [[0 for j in range(n)] for i in range(m)]

for z, *j, in enumerate(Ii):
    for i, k in j:
        I[m-i][k-1] = ci[z]

for i in I:
    print(i)

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[11, 0, 0, 0, 5, 0, 0, 3, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 4, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 5, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

在Python中将两个列表合并到另一个列表

1 个答案: