Question

我有一个很简单的问题：我尝试将以下数据读入数据框https://www.ecdc.europa.eu/en/publications-data/download-data-response-measures-covid-19

如果我使用以下代码，则输出的格式不符合我的期望，因为CSV不是“分隔”的：

dmeasures = pd.read_csv('file.csv',sep=",",header=0,)
print (dmeasures)

有什么主意我的错误是分隔符吗？

Answer 1

您可以直接从URL读取CSV：

url = 'https://www.ecdc.europa.eu/sites/default/files/documents/Data_response_graphs_2020-10-21.csv'
dmeasures = pd.read_csv(url, sep=",")
print(dmeasures)

打印：

            Country            Response_measure  date_start    date_end
0           Austria                 ClosDaycare  2020-03-16  2020-05-04
1           Austria                    ClosHigh  2020-03-16  2020-09-30
2           Austria                    ClosPrim  2020-03-16  2020-05-18
3           Austria                  ClosPubAny  2020-03-16  2020-04-13
4           Austria           ClosPubAnyPartial  2020-04-14         NaN
..              ...                         ...         ...         ...
460  United Kingdom        StayHomeOrderPartial  2020-05-10  2020-07-04
461  United Kingdom               StayHomeRiskG  2020-03-16  2020-07-05
462  United Kingdom        StayHomeRiskGPartial  2020-07-06  2020-08-01
463  United Kingdom         TeleworkingClosures  2020-03-16  2020-05-09
464  United Kingdom  TeleworkingClosuresPartial  2020-05-10         NaN

[465 rows x 4 columns]

Answer 2

url ='https://www.ecdc.europa.eu/sites/default/files/documents/Data_response_graphs_2020-10-21.csv'

pd.read_csv（url，sep =“，”，标头= True）

熊猫错误地读取csv

2 个答案: