我正在尝试对XPathDocument进行序列化和反序列化协议缓冲区消息,但它失败并出现异常: ProtoBuf.ProtoException:消息中检测到的组标记不匹配 我如何使这项工作?
我正在使用protobuf-net,我的源代码用于复制它看起来像这样:
TestMsg.proto
option optimize_for = SPEED;
//*************************
message Test {
repeated A a = 1;
}
message A {
required string str = 1;
}
Progam.cs
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
using System.Xml.XPath;
using ProtoBuf;
using TestMsg;
namespace protocolbufferserialize
{
class Program
{
static void Main(string[] args)
{
Test t = new Test();
XPathDocument xmldoc = Serialize(t);
Test t1 = Serialize(xmldoc);
}
public static XPathDocument Serialize(Test wro)
{
XPathDocument xmlDoc = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(wro.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, wro);
memoryStream.Position = 0;
xmlDoc = new XPathDocument(memoryStream);
}
}
return xmlDoc;
}
public static Test Serialize(XPathDocument xmlDoc)
{
Test t = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(xmlDoc.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, xmlDoc);
memoryStream.Position = 0;
t = Serializer.Deserialize<Test>(memoryStream);
}
}
return t;
}
}
}
我尝试扩展使用Serializer.Merge但是当它从xml返回时,Test对象是空的。
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
using System.Xml.XPath;
using ProtoBuf;
using TestMsg;
namespace TestXMLSerilizationLars
{
class Program
{
static void Main(string[] args)
{
Test t = new Test();
A a = new A();
string str = "test";
a.str = str;
t.a.Add(a);
XPathDocument xmldoc = Serialize(t);
WriteXpathDocument(xmldoc, "c:\\testmsg.xml");
Test t1 = Serialize(xmldoc);
}
public static XPathDocument Serialize(Test t)
{
XPathDocument xmlDoc = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(t.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, t);
memoryStream.Position = 0;
xmlDoc = new XPathDocument(memoryStream);
}
}
return xmlDoc;
}
public static Test Serialize(XPathDocument xmlDoc)
{
Test t = null;
Type type = xmlDoc.GetType();
XmlSerializer serializer = new XmlSerializer(type);
using (MemoryStream memoryStream = new MemoryStream())
{
serializer.Serialize(memoryStream, xmlDoc);
// memoryStream.Close();
Test newt = Deserialize(memoryStream.ToArray());
return newt;
}
return t;
}
static public Test Deserialize(byte[] Bytes)
{
MemoryStream SerializeStream = new MemoryStream(Bytes);
Test NewObject = Serializer.Deserialize<Test>(SerializeStream);
Test ObjectExist = new Test();
if (ObjectExist == null)
{
return NewObject;
}
else
{
SerializeStream.Seek(0, SeekOrigin.Begin);
Serializer.Merge<Test>(SerializeStream, ObjectExist);
return ObjectExist;
}
}
public static void WriteXpathDocument(XPathDocument xpathDoc, string filename)
{
// Create XpathNaviagtor instances from XpathDoc instance.
XPathNavigator objXPathNav = xpathDoc.CreateNavigator();
// Create XmlWriter settings instance.
XmlWriterSettings objXmlWriterSettings = new XmlWriterSettings();
objXmlWriterSettings.Indent = true;
// Create disposable XmlWriter and write XML to file.
using (XmlWriter objXmlWriter = XmlWriter.Create(filename, objXmlWriterSettings))
{
objXPathNav.WriteSubtree(objXmlWriter);
objXmlWriter.Close();
}
}
}
}
我转出的xml文件看起来像这样
<?xml version="1.0" encoding="utf-8"?>
<Test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<a>
<A>
<str>test</str>
</A>
</a>
</Test>
答案 0 :(得分:1)
您在这里使用protobuf的唯一时间是:
x.Serialize(w, xmlDoc);
memoryStream.Position = 0;
t = Serializer.Deserialize<Test>(memoryStream);
你写过xml(x
是XmlSerializer
),然后尝试通过protobuf(Serializer.Deserialize
)读取它。
然而; protobuf不是xml;它是一个与xml无关的二进制格式 。如果您打算深度克隆数据,则还应使用protobuf-net(Serializer.Serialize
)序列化。
通常可以在两种格式之间转换模型,但自身流不可交换。