Question

我用代码创建了下表

 newdf['Year_Date'] = pd.DatetimeIndex(newdf['AbsenceBegDate']).year
 newdf['Week_Number'] = pd.DatetimeIndex(newdf['AbsenceBegDate']).week
 newdf.drop('AbsenceBegDate', axis=1, inplace=True)

newdf：

Emp_ID        Year_Date       Week_Number        Salary         Hours_Worked
5500            2019              30              300              30
3300            2019              31              350              31
3300            2019              32              400              35

我需要从星期数和年份中添加两列“开始日期”和“该周的结束日期”

例如，

Emp_ID        Year_Date       Week_Number        Salary         Hours_Worked     Start_Date      End_Date
5500            2019              30              300              30            07/25/2019        07/31/2019
3300            2019              31              350              31             08/01/2019       08/07/2019
3300            2019              32              400              35            08/08/2019        08/15/2019

您能告诉我如何提取此开始日期和结束日期。感谢您的帮助

Answer 1

您可以创建一个函数来执行此操作：首先定义从哪里开始。例如，这是您今天要作为开始日期执行的操作，当然您可以根据自己的需要进行调整：

today    = date.today()
Week     = today.isocalendar()[1]
pastWeek = Week-1
year     = 2020

，然后定义此功能：

def get_dates(year, week):
     d = date(year,1,1)
     if(d.weekday()<= 3):
         d = d - timedelta(d.weekday())             
     else:
         d = d + timedelta(7-d.weekday())
     dlt = timedelta(days = (week-1)*7)
     return d + dlt,  d + dlt + timedelta(days=6)

已经做到了：

X = get_dates(year, (pastWeek-1) )

为您提供足够的信息来完成这项工作：

Startdate       = str(X[0])
Enddate         = str(X[1])
StartdateNew    = pd.to_datetime(Startdate).date()
EnddateNew      = pd.to_datetime(Enddate).date()
StartdateNew2   = StartdateNew.strftime('%Y%m%d') 
EnddateNew2     = EnddateNew.strftime('%Y%m%d')

Python：从熊猫的周数和年份中计算一周的开始日期和结束日期

1 个答案: