Question

在Terraform中，我需要从以下位置转换我的输入数据结构：

vip_sets = [
    ["1.0.1.1", "1.0.2.1", "1.0.0.1"]
    ["1.0.1.2", "1.0.2.2", "1.0.0.2"]
    ["1.0.1.3", "1.0.2.3", "1.0.0.3"]
    ["1.0.1.4", "1.0.2.4", "1.0.0.4"]
]

产生这样的输出：

    df.style.applymap(alta_baja, subset=['MEDIA']).format({'MEDIA': "{:.1f}"})

所以从本质上讲，我需要获取列表的输入列表并创建一个输出，该输出再次是列表的列表，但其第0个列表是输入中每个列表中第0个元素的列表...然后第一次同样如此，依此类推。我无法预先知道输入中将包含多少个列表，或者它们将有多长，但是我们可以假设这些列表的长度都是一样的。

我已经尝试了几乎所有我能想到的东西，并在网上搜索了，但是从此没有运气。所有建议都将受到欢迎！

Answer 1

这有点可怕，但是可以解决（尽管我没有测试vip_lists为空的情况。可能崩溃，因为我在不检查的情况下索引到vip_lists[0]）：

locals {
  vip_lists = [
    ["1.0.1.1", "1.0.1.2", "1.0.1.3", "1.0.1.4"],
    ["1.0.2.1", "1.0.2.2", "1.0.2.3", "1.0.2.4"],
    ["1.0.0.1", "1.0.0.2", "1.0.0.3", "1.0.0.4"]
  ]

  vip_sets = [for i in range(0, length(local.vip_lists[0])): [for j in range(0, length(local.vip_lists)): local.vip_lists[j][i]]]
}

output "vip_sets" {
  value = local.vip_sets
}

$ terraform apply
Apply complete! Resources: 0 added, 0 changed, 0 destroyed.

Outputs:

vip_sets = [
  [
    "1.0.1.1",
    "1.0.2.1",
    "1.0.0.1",
  ],
  [
    "1.0.1.2",
    "1.0.2.2",
    "1.0.0.2",
  ],
  [
    "1.0.1.3",
    "1.0.2.3",
    "1.0.0.3",
  ],
  [
    "1.0.1.4",
    "1.0.2.4",
    "1.0.0.4",
  ],
]

Answer 2

我曾经为github.com/mineiros-io上的一个模块长度不相同的列表列表编写了该版本的列表，在该列表中，我们使用count使用此类转换来创建二维资源集。（那些未使用的atm，因为我们将它们转换为可用于资源级别for_each的地图）。

locals {
  matrix = [
    ["1.0.1.1", "1.0.1.4"],
    ["1.0.2.1", "1.0.2.2", "1.0.2.3", "1.0.2.4"],
    ["1.0.0.1", "1.0.0.3", "1.0.0.4"]
  ]

  row_lengths = [
    for row in local.matrix : length(row)
  ]

  max_row_length = max(0, local.row_lengths...)

  output = [
    for i in range(0, local.max_row_length) : [
      for j, _ in local.matrix : try(local.matrix[j][i], null)
    ]
  ]

  output_compact = [
    for i in range(0, local.max_row_length) : compact([
      for j, _ in local.matrix : try(local.matrix[j][i], null)
    ])
  ]
}

output "matrix" {
  value = local.output
}

output "compact" {
  value = local.output_compact
}

可以处理动态列表大小，并以紧凑的形式或以null值填充来输出：

Outputs:

compact = [
  [ "1.0.1.1", "1.0.2.1", "1.0.0.1" ],
  [ "1.0.1.4", "1.0.2.2", "1.0.0.3" ],
  [ "1.0.2.3", "1.0.0.4" ],
  [ "1.0.2.4" ],
]

matrix = [
  [ "1.0.1.1", "1.0.2.1", "1.0.0.1" ],
  [ "1.0.1.4", "1.0.2.2", "1.0.0.3" ],
  [ null,      "1.0.2.3", "1.0.0.4" ],
  [ null,      "1.0.2.4", null      ],
]

我知道答案已经被接受，但是也许有人仍然可以使用此动态版本。

Terraform-将列表列表转换为新的列表列表

2 个答案: