我使用SwiftUI列表,并通过绑定将字符串传递给其他视图。 但是当我返回时,列表没有更新。
这是我的例子:
struct ContentView: View {
@State private var list = ["a", "b", "c"]
@State private var item: String?
@State private var showSheet = false
var body: some View {
List {
ForEach(list.indices) { i in
Button(action: {
item = list[i]
showSheet.toggle()
}) {
Text(list[i])
}
}
}
.sheet(isPresented: $showSheet, content: {
DetailView(input: $item)
})
}
}
详细信息页面:
struct DetailView: View {
@Binding var input: String?
var body: some View {
Text(input ?? "")
.onDisappear{
print("changed to changed")
input = "changed"
}
}
}
我想要实现的是,在我单击的每个项目上,我都可以看到详细信息页面。之后,该元素应更改为“更改”。但这不会发生。为什么?
答案 0 :(得分:1)
您更新了item
,但没有更新list
,因此看不到任何结果。这是经过纠正的变体-存储选定的索引,并将绑定传递给按索引列出。
通过Xcode 12.1 / iOS 14.1测试
struct ContentView: View {
@State private var list = ["a", "b", "c"]
@State private var item: Int?
var body: some View {
List {
ForEach(list.indices) { i in
Button(action: {
item = i
}) {
Text(list[i])
}
}
}
.sheet(item: $item, content: { i in
DetailView(input: $list[i])
})
}
}
extension Int: Identifiable {
public var id: Self { self }
}
struct DetailView: View {
@Binding var input: String
var body: some View {
Text(input)
.onDisappear{
print("changed to changed")
input = "changed"
}
}
}
答案 1 :(得分:1)
我建议您使用.sheet(item:content:)
代替.sheet(isPresented:content:)
struct ContentView: View {
@State private var items = ["a", "b", "c"]
@State private var selectedIndex: Int?
var body: some View {
List {
ForEach(items.indices) { index in
Button(action: {
selectedIndex = index
}) {
Text(items[index])
}
}
}
.sheet(item: $selectedIndex) { index in
DetailView(item: $items[index])
}
}
}
struct DetailView: View {
@Binding var item: String
var body: some View {
Text(item)
.onDisappear {
print("changed to changed")
item = "changed"
}
}
}
但是,这将要求selectedIndex
符合Identifiable
。
您可以创建一个Int
扩展名:
extension Int: Identifiable {
public var id: Int { self }
}
或为您的数据创建自定义结构(并符合Identifiable
)。