Question

我正在开发一个Android，我希望使用NETWORK_PROVIDER获取用户位置，我没有使用GPS用于此目的。我正在跟踪异常

java.lang.SecurityException：需要ACCESS_FINE_LOCATION或ACCESS_COARSE_LOCATION权限

我正在使用以下代码。]

tx=(TextView) findViewById(R.id.textView1);
    lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    lm.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 1000,
    10f, this);
    tx.setText("Status="+lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER));

和清单文件

<application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity android:name=".MainActivity" android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
    <uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
    <uses-permission android:name="android.permission.INTERNET" />
</application>

Answer 1

权限放在清单标签中（不在应用程序标签中），即

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="package.mypackage" android:versionCode="1" android:versionName="1.2">
<uses-sdk android:minSdkVersion="7" />

<application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity android:name=".MainActivity" android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

</application>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />
</manifest>

Answer 2

请尝试

<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".MainActivity" android:label="@string/app_name">
    <intent-filter>
        <action android:name="android.intent.action.MAIN" />
        <category android:name="android.intent.category.LAUNCHER" />
    </intent-filter>
</activity>
</application>

<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />

java.lang.SecurityException：需要ACCESS_FINE_LOCATION或ACCESS_COARSE_LOCATION权限

2 个答案: