无法在Django中迁移模型

时间:2020-11-03 09:57:23

标签: python mysql django pandas django-models

一切都很好,但我不知道为什么我一次又一次收到此错误。我的行大小没有超过,我也将CharFields更改为文本,但同样的错误再次出现。请帮我解决这个问题。

错误消息-

django.db.utils.OperationalError:(1118,'行大小太大。 所用表类型的最大行大小(不计算BLOB)为 65535。这包括存储开销,请查阅手册。您必须将某些列更改为TEXT或BLOB')

from django.db import models

# Create your models here.
'''class App(models.Model):
    description = models.CharField(max_length=100)
    price = models.DecimalField(max_digits=9,decimal_places=2)
    quantity = models.IntegerField()
    #media = models.FileField(upload_to='media', default="")
    def __str__(self):
        return self.description
'''
class JD(models.Model):
    Title = models.CharField(max_length=1000)
    Location = models.CharField(max_length=1000)
    Experience = models.CharField(max_length=1000)
    Company = models.CharField(max_length=1000)
    Description = models.CharField(max_length=1000)

    def __str__(self):
        return self.Title


class JDrefined(models.Model):
    Title = models.CharField(max_length=100)
    Location = models.CharField(max_length=100)
    Experience = models.CharField(max_length=100)
    Company = models.CharField(max_length=100)
    Description = models.CharField(max_length=1000)
    Designation = models.CharField(max_length=100)
    TechSkillMatch = models.CharField(max_length=100)
    SoftSkillMatch = models.CharField(max_length=100)
    JobType = models.CharField(max_length=100)
    Tskills = models.CharField(max_length=100)
    Sskills = models.CharField(max_length=100)
    Techskill1 = models.CharField(max_length=100)
    Techskill2 = models.CharField(max_length=100)
    Techskill3 = models.CharField(max_length=100)
    Techskill4 = models.CharField(max_length=100)
    Techskill5 = models.CharField(max_length=100)
    Softskill1 = models.CharField(max_length=100)
    Softskill2 = models.CharField(max_length=100)
    Softskill3 = models.CharField(max_length=100)
    Softskill4 = models.CharField(max_length=100)
    Softskill5 = models.CharField(max_length=100)

    def __str__(self):
        return self.Title

0 个答案:

没有答案
相关问题