Question

我正在制作一个可以通过多个条件过滤列表的应用。我正在做的是一个看起来像这样的对象数组：

{
list :[array],
amount: 15000,
type: state,
zipCode: 9xxxx
}

所以我决定使用一个case开关进行一次forEach迭代，该case开关贯穿对象字面量，找出条件的真实性，然后过滤列表。我可以使用下面的代码来运行大多数过滤器，并获得唯一列表。但是由于某种原因，如果我将zipCodeSuppress放入案例中，那么如果将其置于大小写开关的顶部，则将获得0次点击；如果将其置于大小写开关的底部，则不会对其进行注册。

这是代码。任何帮助都很好

 drop.forEach( async (tollFree) => {
      //console.log(Object.entries(tollFree));
      const zipCodes = Object.values(tollFree)[0].split(",");
     //   console.log(tollFree)

      let updatedList = []
      const {
        lienType,
        tracking,
        mailList,
        lienAmount,
        vendor,
        postageCeiling,
        unitCost,
        mailHouse,
        date,
        title, 
        zipCodeSuppress,
      } = tollFree;


   console.log(zipCodeSuppress)

   zips = await Zip.find({
    "class": { "$in": zipCodes },
  });
   
  zips = zips.map(zip => zip.zip4)

   switch (true) {
        case zipCodeSuppress == "keepSelect":
          updatedList.push(mailList.filter((e) => zips.includes(e.zip4.substring(0,4))))
          break;
        case lienAmount == "15000":
          updatedList.push(mailList.filter((e) => e.amount <= 15000));
          break;
        case lienAmount == "25000":
        updatedList.push(mailList.filter(
            (e) => e.amount >= 15000 && e.amount <= 25000
          ));
          break;
        case lienAmount == "50000":
        updatedList.push(mailList.filter((e) => e.amount >= 25000 && e.amount <= 50000));
          break;
        case lienAmount == "100000":
        updatedList.push(mailList.filter(
            (e) => e.amount >= 50000 && e.amount <= 100000
          ));
          break;
        case lienAmount == "10000000":
          updatedList.push(mailList.filter((e) => e.amount > 100000));
          break;
        case vendor == "ftls":
          updatedList.push(mailList.filter((e) => e.pinCode.length === 7));
          break;
        case vendor == "risk":
          updatedList.push(mailList.filter((e) => e.pinCode.length === 10));
          break;
        case vendor == "advance":
          updatedList.push(mailList.filter((e) => e.pinCode.length === 12));
          break;
        case vendor == "atype":
          updatedList.push(mailList.filter((e) => e.pinCode.length === 15));
          break;
        case lienType == "state":
         updatedList.push(mailList.filter((e) => e.fileType == "State Tax Lien"));
          break;
        case lienType == "federal":
         updatedList.push(mailList.filter((e) => e.fileType == "Federal Tax Lien"));
          break;
        default:
          return mailList;
      }
      updatedList = updatedList.flat()

      console.log(updatedList.length)
    })

Answer 1

switch/case仅执行匹配的第一种情况。因此，如果zipCodeSuppress == "keepSelect"为true，则不会检查其他任何条件。

对于每个变量，您应该使用单独的switch/case。

switch (zipCodeSuppress) {
  case "keepSelect":
    updatedList.push(mailList.filter((e) => zips.includes(e.zip4.substring(0, 4))))
    break;
}
switch (lienAmount) {
  case "15000":
    updatedList.push(mailList.filter((e) => e.amount <= 15000));
    break;
  case "25000":
    updatedList.push(mailList.filter(
      (e) => e.amount >= 15000 && e.amount <= 25000
    ));
    break;
  case "50000":
    updatedList.push(mailList.filter((e) => e.amount >= 25000 && e.amount <= 50000));
    break;
  case "100000":
    updatedList.push(mailList.filter(
      (e) => e.amount >= 50000 && e.amount <= 100000
    ));
    break;
  case "10000000":
    updatedList.push(mailList.filter((e) => e.amount > 100000));
    break;
}
switch (vendor) {
  case "ftls":
    updatedList.push(mailList.filter((e) => e.pinCode.length === 7));
    break;
  case "risk":
    updatedList.push(mailList.filter((e) => e.pinCode.length === 10));
    break;
  case "advance":
    updatedList.push(mailList.filter((e) => e.pinCode.length === 12));
    break;
  case "atype":
    updatedList.push(mailList.filter((e) => e.pinCode.length === 15));
    break;
}
switch (lienType) {
  case "state":
    updatedList.push(mailList.filter((e) => e.fileType == "State Tax Lien"));
    break;
  case "federal":
    updatedList.push(mailList.filter((e) => e.fileType == "Federal Tax Lien"));
    break;
}

案例切换过滤器

1 个答案: