如何在Flutter中调整图像的色相饱和度和亮度?

时间:2020-11-02 03:54:27

标签: flutter dart image-processing colormatrix

在Flutter应用中,我有一张图像和三个滑块,一个用于色调,一个用于饱和度,一个用于亮度,并且我正在尝试找出如何使用ColorFiltered小部件进行这些调整,但是我无法弄清楚ColorFilter.matrix的内容。

我的代码如下:

ColorFiltered(
  colorFilter: ColorFilter.matrix(
    // What goes here?
  ),
  child: Container(
    decoration: BoxDecoration(
      image: DecorationImage(
        fit: BoxFit.cover,
        image: NetworkImage(myImageUrl),
      )
    )
  )
)

有人知道如何根据HSV值生成滤色器矩阵吗?

2 个答案:

答案 0 :(得分:0)

为解决此问题,我构建了一个ImageFilter小部件,可以像这样使用它:

ImageFilter(
  hue: 0.1,
  brightness: -0.6,
  saturation: 0.8,
  child: Container(
    decoration: BoxDecoration(
      image: DecorationImage(
        fit: BoxFit.cover,
        image: NetworkImage(imageUrl),
      ),
    )
  )
)

它以-1和1之间的十进制形式输入百分比。

使用3层ColorFiltered小部件:

Widget ImageFilter({brightness, saturation, hue, child}) {
  return ColorFiltered(
    colorFilter: ColorFilter.matrix(
      ColorFilterGenerator.brightnessAdjustMatrix(
        value: brightness,
      )
    ),
    child: ColorFiltered(
      colorFilter: ColorFilter.matrix(
        ColorFilterGenerator.saturationAdjustMatrix(
          value: saturation,
        )
      ),
      child: ColorFiltered(
        colorFilter: ColorFilter.matrix(
          ColorFilterGenerator.hueAdjustMatrix(
            value: hue,
          )
        ),
        child: child,
      )
    )
  );
}

要生成过滤器矩阵,我使用了以下答案的帮助,以解决类似的Android问题:https://stackoverflow.com/a/7917978/937841,并创建了一个ColorFilterGenerator可以在颤动下工作:

import 'dart:math';

class ColorFilterGenerator {
    static List<double> hueAdjustMatrix({double value}) {
      value = value * pi;

      if (value == 0)
        return [
          1,0,0,0,0,
          0,1,0,0,0,
          0,0,1,0,0,
          0,0,0,1,0,
        ];

      double cosVal = cos(value);
      double sinVal = sin(value);
      double lumR = 0.213;
      double lumG = 0.715;
      double lumB = 0.072;

      return List<double>.from(<double>[
        (lumR + (cosVal * (1 - lumR))) + (sinVal * (-lumR)), (lumG + (cosVal * (-lumG))) + (sinVal * (-lumG)), (lumB + (cosVal * (-lumB))) + (sinVal * (1 - lumB)), 0, 0, (lumR + (cosVal * (-lumR))) + (sinVal * 0.143), (lumG + (cosVal * (1 - lumG))) + (sinVal * 0.14), (lumB + (cosVal * (-lumB))) + (sinVal * (-0.283)), 0, 0, (lumR + (cosVal * (-lumR))) + (sinVal * (-(1 - lumR))), (lumG + (cosVal * (-lumG))) + (sinVal * lumG), (lumB + (cosVal * (1 - lumB))) + (sinVal * lumB), 0, 0, 0, 0, 0, 1, 0,
      ]).map((i) => i.toDouble()).toList();
    }

    static List<double> brightnessAdjustMatrix({double value}}) {
      if (value <= 0)
        value = value * 255;
      else value = value * 100

      if (value == 0)
        return [
          1,0,0,0,0,
          0,1,0,0,0,
          0,0,1,0,0,
          0,0,0,1,0,
        ];

      return List<double>.from(<double>[
        1, 0, 0, 0, value, 0, 1, 0, 0, value, 0, 0, 1, 0, value, 0, 0, 0, 1, 0
      ]).map((i) => i.toDouble()).toList();
    }

    static List<double> saturationAdjustMatrix({double value}) {
      value = value * 100;

      if (value == 0)
        return [
          1,0,0,0,0,
          0,1,0,0,0,
          0,0,1,0,0,
          0,0,0,1,0,
        ];

      double x = ((1 + ((value > 0) ? ((3 * value) / 100) : (value / 100)))).toDouble();
      double lumR = 0.3086;
      double lumG = 0.6094;
      double lumB = 0.082;

      return List<double>.from(<double>[
        (lumR * (1 - x)) + x, lumG * (1 - x), lumB * (1 - x),
        0, 0,
        lumR * (1 - x),
        (lumG * (1 - x)) + x,
        lumB * (1 - x),
        0, 0,
        lumR * (1 - x),
        lumG * (1 - x),
        (lumB * (1 - x)) + x,
        0, 0, 0, 0, 0, 1, 0,
      ]).map((i) => i.toDouble()).toList();
    }
}

我敢打赌,有一种方法可以连接色相/饱和度/亮度矩阵(就像我在上面提到的android问题中所做的那样),并且仅使用1个颜色过滤的矩阵(可能会更有效),但是这适用于我的情况。

答案 1 :(得分:0)

我们必须在其中包含一个颜色矩阵。 一些例子是:

static const ColorFilter sepia = ColorFilter.matrix(<double>[
 0.393, 0.769, 0.189, 0, 0,
 0.349, 0.686, 0.168, 0, 0,
 0.272, 0.534, 0.131, 0, 0,
 0,     0,     0,     1, 0]);

static const ColorFilter greyscale = ColorFilter.matrix(<double>[
 0.2126, 0.7152, 0.0722, 0, 0,
 0.2126, 0.7152, 0.0722, 0, 0,
 0.2126, 0.7152, 0.0722, 0, 0,
 0,      0,      0,      1, 0]);

只需复制上面的矩阵即可获得棕褐色或灰度滤镜。