Question

UNIT="CCC62"

echo $UNIT |
gawk '{match($0,/(.){4}/,a)}{if (a[1] == 7 || a[1] == 6) print $0}'

如果变量的第4个字符是“ 6”或“ 7”，则上面的结果会产生预期的/期望的结果，然后打印该行，但是有没有办法将变量放入gawk的代码中并获得相同的结果？并且有一种更聪明的方式仅使用gawk进行以下操作吗？

Answer 1

能否请您尝试以下操作，也请在代码中解决您的问题。

unit="CCC62"
gawk -v var="$unit" 'BEGIN{split(var,a,"");if (a[4] == 7 || a[4] == 6) print var}'

说明： 添加以上详细说明。

unit="CCC62"                      ##shell variable
gawk -v var="$unit" '             ##Starting gawk program and sending shell variable unit to awk variable var here -v is ideal way of doing so.
BEGIN{                            ##Since there is NO Input_file so work will be done within BEGIN section only.
                                  ##Which works without mentioning Input_file name too.
  split(var,a,"")                 ##Splitting var into array a with separator of NULL.
  if(a[4] == 7 || a[4] == 6){     ##Checking condition if 4th element of a is either 7 or  6 if yes then do following.
    print var                     ##printing value of var here.
  }
}'

有没有一种方法可以使用变量而不在“ gawk”中使用“ echo”？

1 个答案: