Question

当我尝试在jupyter笔记本中使用Java内核时，出现以下错误消息：

    Traceback (most recent call last):
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\web.py", line 1703, in _execute
    result = await result
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\ProgramData\Anaconda3\lib\site-packages\notebook\services\sessions\handlers.py", line 69, in post
    model = yield maybe_future(
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\ProgramData\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 88, in create_session
    kernel_id = yield self.start_kernel_for_session(session_id, path, name, type, kernel_name)
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\ProgramData\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 100, in start_kernel_for_session
    kernel_id = yield maybe_future(
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\ProgramData\Anaconda3\lib\site-packages\tornado\gen.py", line 209, in wrapper
    yielded = next(result)
  File "C:\ProgramData\Anaconda3\lib\site-packages\notebook\services\kernels\kernelmanager.py", line 168, in start_kernel
    super(MappingKernelManager, self).start_kernel(**kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\jupyter_client\multikernelmanager.py", line 186, in start_kernel
    km.start_kernel(**kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\jupyter_client\manager.py", line 308, in start_kernel
    self.kernel = self._launch_kernel(kernel_cmd, **kw)
  File "C:\ProgramData\Anaconda3\lib\site-packages\jupyter_client\manager.py", line 215, in _launch_kernel
    return launch_kernel(kernel_cmd, **kw)
  File "C:\ProgramData\Anaconda3\lib\site-packages\jupyter_client\launcher.py", line 135, in launch_kernel
    proc = Popen(cmd, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\subprocess.py", line 854, in __init__
    self._execute_child(args, executable, preexec_fn, close_fds,
  File "C:\ProgramData\Anaconda3\lib\subprocess.py", line 1307, in _execute_child
    hp, ht, pid, tid = _winapi.CreateProcess(executable, args,
PermissionError: [WinError 5] Access is denied

如何解决此错误？我通过anaconda导航器使用jupyter笔记本，我已经尝试以管理员身份运行它。应该通过文件资源管理器访问所有有问题的文件。

如何修复PermissionError：[WinError 5] Jupyter笔记本电脑上的Acces被拒绝？

0 个答案: