如何从id discord.py获取用户对象

时间:2020-10-30 13:46:46

标签: python discord.py

我有一个机器人,它会将dm ping发送给用户,该用户的ID作为命令中的参数给出。
这是命令:.spam ID #_OF_PINGS
我遇到以下错误:

Ignoring exception in command spam:
Traceback (most recent call last):
File "/app/.heroku/python/lib/python3.6/site-packages/discord/ext/commands/core.py", line 85, in wrapped
ret = await coro(*args, **kwargs)
File "bot.py", line 16, in spam
     await ctx.send(f'Started pinging {user.name} {num} times.')
AttributeError: 'NoneType' object has no attribute 'name'

The above exception was the direct cause of the following exception:
Traceback (most recent call last):
   File "/app/.heroku/python/lib/python3.6/site-packages/discord/ext/commands/bot.py", line 903, in invoke
     await ctx.command.invoke(ctx)
   File "/app/.heroku/python/lib/python3.6/site-packages/discord/ext/commands/core.py", line 859, in invoke
     await injected(*ctx.args, **ctx.kwargs)
    File "/app/.heroku/python/lib/python3.6/site-packages/discord/ext/commands/core.py", line 94, in wrapped
     raise CommandInvokeError(exc) from exc
     discord.ext.commands.errors.CommandInvokeError: Command raised an exception: AttributeError: 'NoneType' object has no attribute 'name'

这是我的代码:

from discord.ext import commands
token = 'MyBotTokenHere'
prefix = '.'
client = commands.Bot(command_prefix=prefix)
client.remove_command("help")


@client.event
async def on_ready():
    print('Ready')


@client.command()
async def spam(ctx, id1: int, num: int):
    user = client.get_user(id1)
    await ctx.send(f'Started pinging {user.name} {num} times.')
    for i in range(num):
        await user.send(f'<@{str(id1)}>')
    await ctx.send(f'Finished {num} pings for {user.name}')


client.run(token)

昨天工作正常,但今天由于某种原因它坏了。 如何解决?
附言我将其托管在Heroku上

1 个答案:

答案 0 :(得分:1)

您可以为此使用转换器:

@client.command()
async def spam(ctx, user: discord.User, num: int):
    await ctx.send(f'Started pinging {user.name} {num} times.')
    for i in range(num):
        await user.send(f'<@{str(id1)}>')
    await ctx.send(f'Finished {num} pings for {user.name}')

通过这种方式,Discord将自动尝试获取与您作为参数传递的discord.User相对应的id实例,如果您想&也可以@mention某人&仍然可以。

此外,从Discord 1.5.0开始,您现在需要在初始化机器人时传递intents,您显然还没有这样做。更新您的Discord,并使用以下内容初始化您的漫游器:

intents = discord.Intents.default()
intents.members = True
client = commands.Bot(command_prefix=prefix, intents=intents)

有关API documentationintents的方式和原因的更多信息。您还需要在机器人的Privileged Intents页面上启用members,链接的API文档中也对此进行了说明。

相关问题