Question

嘿，我正在尝试将这两个列表合并为一个字典。但是，在第二个for循环中，它只会继续执行该操作，而不会返回第一个。任何帮助将非常感激。谢谢！

import random
chores = ['dishes','bathroom','vacuum','walk dog']
assign = {}
emails = ['a','b','c','d']

x=0
while x < 4:
    for i in chores:
        randomChore = random.choice(chores)
        chores.remove(randomChore)
    
        for key in emails: 
            assign[key] = randomChore
            x = x + 1

Answer 1

您只需要random.shuffle，它的工作原理就是这样

import random

chores = ['dishes','bathroom','vacuum','walk dog']
assign = {}
emails = ['a','b','c','d']

random.shuffle(chores)
res = {key:val for key,val in zip(emails,chores)}

Answer 2

在您的代码中，for key in emails: 部分需要删除。它会选择随机的杂项然后循环浏览，添加电子邮件而不会选择其他随机的杂项。

这是工作代码。

import random
chores = ['dishes','bathroom','vacuum','walk dog']
assign = {}
emails = ['a','b','c','d']

x = 0
for i in range(0, len(chores)):
    randomChore = random.choice(chores)
    chores.remove(randomChore)

    assign[emails[x]] = randomChore
    x = x + 1
    
print(assign)

Answer 3

这里，您不需要无用的内部，而无需循环遍历遍历键：

import random
chores = ['dishes','bathroom','vacuum','walk dog']
assign = {}
emails = ['a','b','c','d']


for i in emails:
  randomChore = random.choice(chores)
  chores.remove(randomChore)
  assign[i] = randomChore

print(assign)

随机组合两个列表

3 个答案: