检查本地存储中是否已经存在用户

时间:2020-10-29 12:13:23

标签: javascript html arrays dom local-storage

const firstName = document.getElementById("firstName");
const lastnName = document.getElementById("lastName");
const email = document.getElementById("newEmail");
const password = document.getElementById("newPassword");

const btnSignup = document.getElementById("btn-signup");

btnSignup.onclick = function () { // when mouse click "signup" button
    const first_name = firstName.value; // getting the value of firstName and so on..
    const last_name = lastName.value;
    const e_mail = newEmail.value;
    const pass_word = newPassword.value;

    if (first_name && last_name && e_mail && pass_word) {
 
        //set user input into JSON
        let user_data = {
            firstName: first_name,
            lastName: last_name,
            email: e_mail,
            password: pass_word
        }
        
        //get to localstorage if there is existing user ||or make empty array[]
        let clientsArr = JSON.parse(localStorage.getItem('users')) || [];
        
        //ipush ang new user sa array
        clientsArr.push(user_data);

        //save to localstorage
        localStorage.setItem('users', JSON.stringify(clientsArr));
    }
        // location.reload();
        else if (user_data === localStorage.getItem('users')) { // THIS IS THE CODE THAT I AM TRYING
            alert("User already existed");
        } 
};

我正在尝试在屏幕上显示错误消息或在浏览器上发出警告,此代码实际上有效,问题是如何识别本地存储中是否存在现有用户。我要说的是,如果内存中存在现有用户,则您的“登录”将不接受。谢谢!我对要运行的代码添加了注释。

2 个答案:

答案 0 :(得分:1)

几点:

  • JavaScript通过内存引用(RAM上的位置)比较对象。
  • let变量绑定到词法范围{}。因此,user_data在第二个else if语句中将不可用。
  • 奖励:使用早期退出功能以保持代码干净。
  • 使用唯一标识符,例如id。在示例中,我将对象转换为字符串并进行比较。

// Fields
const firstName = document.getElementById("firstName");
const lastnName = document.getElementById("lastName");
const email = document.getElementById("newEmail");
const password = document.getElementById("newPassword");
// Button
const btnSignup = document.getElementById("btn-signup");

function signUp() {

  const first_name = firstName.value;
  const last_name = lastName.value;
  const e_mail = newEmail.value;
  const pass_word = newPassword.value;

  // If either of the values is empty
  if (!first_name || !last_name || !e_mail || !pass_word) {
    return;
  }

  //set user input into JSON
  let user_data = {
    firstName: first_name,
    lastName: last_name,
    email: e_mail,
    password: pass_word
  }
  
  // convert to string
  let user_data_str = JSON.stringify(user_data)

  //get to localstorage if there is existing user ||or make empty array[]
  let clientsArr = JSON.parse(localStorage.getItem('users')) || [];
  
  // Convert to string
  
  // Search the list if 
  const userExists = clientsArr.find(user => JSON.stringify(user) === user_data_str);
  
  if (userExists) {
    return alert('User already exists')
  }
    
  //ipush ang new user sa array
  clientsArr.push(user_data);

  //save to localstorage
  localStorage.setItem('users', JSON.stringify(clientsArr));

}
// Attach listener
btnSignup.addEventListener('click', signUp);
<input id="firstName" />
<input id="lastName" />
<input id="newEmail" />
<input id="newPassword" />
<button id="btn-signup">Sign up</button>

答案 1 :(得分:0)

如果要在添加到localStorage中的“用户”之前尝试检查用户是否已经存在,则可以执行以下操作:

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