Question

我正在试图弄清楚是否有些动态填充类中的对象数组，而不使用数组初始化。我真的想避免逐行填充数组。根据我在这里的代码，这可能吗？

final class Attributes {

    private final int TOTAL_ATTRIBUTES = 7;

    Attribute agility;
    Attribute endurance;
    Attribute intelligence;
    Attribute intuition;
    Attribute luck;
    Attribute speed;
    Attribute strength;

    private Attributes[] attributes; //array to hold objects

    private boolean initialized = false;

    public Attributes() {
        initializeAttributes();
        initialized = true;

        store(); //method for storing objects once they've been initialized.

    }

    private void initializeAttributes() {
        if (initialized == false) {
            agility = new Agility();
            endurance = new Endurance();
            intelligence = new Intelligence();
            intuition = new Intuition();
            luck = new Luck();
            speed = new Speed();
            strength = new Strength();
        }
    }

    private void store() {
        //Dynamically fill "attributes" array here, without filling each element line by line.
    }
}

Answer 1

attributes = new Attributes[sizeOfInput];

for (int i=0; i<sizeOfInput; i++) {
    attributes[i] = itemList[i];
}

此外，您可以将内容添加到ArrayList，然后调用toArray（）以获取该对象的数组。

Answer 2

有一个简短的数组初始化语法：

attributes = new Attribute[]{luck,speed,strength,etc};

Answer 3

 Field[] fields =  getClass().getDeclaredFields();
 ArrayList<Attrubute> attributesList = new ArrayList<Attrubute>();
 for(Field f : fields)
 {
     if(f.getType() == Attrubute.class)
     {
         attributesList.add((Attrubute) f.get(this));
     }
 }
 attributes = attributesList.toArray(new Attrubute[0]);

Answer 4

您可以使用HashMap<String,Attribute>

Java：动态填充数组（不是vector / ArrayList）

4 个答案: